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Pepsi [2]
3 years ago
8

What mass of glucose (C6H1206) can form from

Chemistry
1 answer:
JulsSmile [24]3 years ago
8 0

Answer: The Answer is 49.05

Explanation:

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Choose the FALSE statement.
Mariana [72]

Answer:

C. The half-life of C-14 is about 40,000 years.

Explanation:

The only false statement from the options is that the half-life of C-14 is 40,000yrs.

The half-life of an isotope is the time it takes for half of a radioactive material to decay to half of its original amount. C-14 has an half-life of 5730yrs. This implies that during every 5730yrs, C-14 will reduce to half of its initial amount.

  • All living organisms contain both stable C-12 and the unstable isotope of C-14
  • The lower the C-14 compared to the C-12 ratio in an organism, the older it is.
5 0
3 years ago
The _____ method of pest control combines chemical and non-chemical methods and emphasizes the use of natural toxins.
labwork [276]
The answer to the question stated above is:
Integrated Pest Management is a method of agricultural pest control that combines chemical and non <span>chemical methods and emphasizes the use of natural toxins and effective pesticide.

>>N</span><span>atural toxins in plants can also be isolated and applied to crops like synthetic pesticides.</span>
4 0
3 years ago
Read 2 more answers
How many is the maximum number of electrons for n=4
mihalych1998 [28]
In Chemistry, to better determine the position of a certain electron, quantum numbers are used. The four quantum numbers are n, l, m and s. In the given above of n= 4, the principal quantum number is 4 and this represents the overall relative energy in the orbital. This means that we are to find the maximum number of electrons in fourth main energy level and the answer is 32. 
7 0
3 years ago
What is the source of the electrons produced in beta decay
Vitek1552 [10]

Answer:

Beta rays are electrons.

Explanation:

A neutron in the nucleus of  a radioactive atom decays into a proton and an electron, which is emitted from the atom.

8 0
3 years ago
Determine the mass (in grams) of 8.02 x 1024 atoms of mercury (Hg).
Virty [35]
<h3>Answer:</h3>

2670 g Hg

<h3>General Formulas and Concepts: </h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation: </h3>

<u>Step 1: Define</u>

8.02 × 10²⁴ atoms Hg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Hg - 200.59 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 8.02 \cdot 10^{24} \ atoms \ Hg(\frac{1 \ mol \ Hg}{6.022 \cdot 10^{23} \ atoms \ Hg})(\frac{200.59 \ g \ Hg}{1 \ mol \ Hg})
  2. Divide/Multiply:                                                                                               \displaystyle 2671.42 \ g \ Hg

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2671.42 g Hg ≈ 2670 g Hg

3 0
3 years ago
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