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yarga [219]
3 years ago
9

Easy Chemistry/ Help

Chemistry
1 answer:
Sauron [17]3 years ago
4 0
I’m not really sure what the qn is asking for but if i’m not wrong it should be ‘1’ for each blank!
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What is the vapor pressure of an aqueous solution made up of 60.0g of urea (CH4N2O) in 180g of water? the vapor pressure of wate
djyliett [7]
To get the answer you use the Law of Raoult.


Raoult's law states that the decrease of the vapor pressure of a liquid is proportional to the molar fraction of the solute.


ΔP = Pa * Xa


Here Pa = 0.038 atm


And Xa = N a / (Na + Nb), where Na is number of moles of A and Nb is number of moles of b


Na = mass of urea / molar mass of urea =  60 g / (molar mass of CH4N2O)


molar mass of CH4N2O = 12 g/mol + 4*1g/mol + 2*14 g/mol + 16 g/mol = 60 g/mol


Na = 60 g / 60 g/mol = 1 mol


Nb = mass of water / molar mass of water = 180g / 18g/mol = 10 mol


Xa = 1 mol / (10 mol + 1 mol) = 1/11 =0.09091


ΔP = Pb * Xa = 0.038 atm * 0.09091 =  0.0035 atm


Then, the final vapor pressure of water is Pb - ΔP = 0.038atm - 0.0035atm = 0.035 atm.


 Answer: 0.035 atm
7 0
4 years ago
A solution has a hydrogen ion concentration of 0.001 M, what is the pH of the solution
LenKa [72]
PH= −log
10
​
[H
+
]
= −log
10
​
(0.001)
= −log
10
​
(10
−3
)
= −(−3)log
10
​
10
pH=3.
01
4 0
3 years ago
For years, surgeons have had great success using _____.
FrozenT [24]
C the artifical heart
6 0
3 years ago
Read 2 more answers
Select the correct answer. Two charged objects, A and B, exert an electric force on each other. What happens if the distance bet
VikaD [51]

Answer:

The electric force between them decreases

Explanation:

The force between two charged particle is given by :

F=\dfrac{kq_1q_2}{r^2}

Where

r is the distance between charges

If the distance between the charges is increased, the electric force gets decreased as there is an inverse relation between force and distance.

Hence, the correct option is (c) "The electric force between them decreases"

7 0
2 years ago
The decomposition of SOCl2 is first-order in SOCl2. If the half-life for the reaction is 4.1 hr, how long would it take for the
qaws [65]
4.1 h = 14760 s 

<span>t 1/2 = ln 2 / k </span>

<span>k = rate reaction = 4.97 x 10^-5 </span>

<span>ln 0.045 / 0.36 = - 4.97 x 10^-5 t </span>

<span>2.08 = 4.97 x 10^-5 t </span>

<span>t = 41839.9 s = 11 h 37 min 19 s</span>
3 0
3 years ago
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