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yarga [219]
3 years ago
9

Easy Chemistry/ Help

Chemistry
1 answer:
Sauron [17]3 years ago
4 0
I’m not really sure what the qn is asking for but if i’m not wrong it should be ‘1’ for each blank!
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Which two reactants make Calcium carbonate?
Norma-Jean [14]

Impossible to form from given reactants

Explanation:

Only sodium has carbonate ion here .so only possible way to displace carbonate is to use potassium

When sodium carbonate and Potassium iodide react with each other double displacement reaction occurs

As potassium is powerful than sodium it displaces sodium to form potassium carbonate .

Then you have to use water and then you can use calcium suppliment .

3 0
2 years ago
Read 2 more answers
21-B. Mn was used as an internal standard for measuring Fe by atomic absorption. A standard mixture containing 2.00 mg Mn/mL and
Korvikt [17]

Answer:

0.0693M Fe

Explanation:

It is possible to quantify Fe in a sample using Mn as internal standard using response factor formula:

F = A(analyte)×C(std) / A(std)×C(analyte) <em>(1)</em>

Where A is area of analyte and std, and C is concentration.

Replacing with first values:

F = 1.05×2.00mg/mL / 1.00×2.50mg/mL

<em>F = 0.84</em>

In the unknown solution, concentration of Mn is:

13.5mg/mL × (1.00mL/6.00mL) = <em>2.25 mg Mn/mL</em>

Replacing in (1) with absorbances values and F value:

0.84 = 0.185×2.25mg/mL / 0.128×C(analyte)

C(analyte) = <em>3.87 mg Fe / mL</em>

As molarity is moles of solute (Fe) per liter of solution:

\frac{3.87 mg Fe}{mL} \frac{1g}{1000mg} \frac{1mol}{55.845g} \frac{1000mL}{1L} = <em>0.0693M Fe</em>

7 0
3 years ago
Read 2 more answers
Where does secretion occur in the nephron?
grin007 [14]
Inside the glomerular capsule at the glomerulus
7 0
3 years ago
A compound that is composed of molybdenum (Mo) and oxygen (O) was produced in a lab by heating molybdenum over a Bunsen burner.
irakobra [83]
First, we determine the mass of each element from the data collected. We can get the mass of molybdenum Mo from the difference between the mass of crucible and molybdenum and the mass of crucible:
     Mass of molybdenum = 39.52 – 38.26 = 1.26 g Mo

We can calculate for the mass of molybdenum oxide from the difference between the mass of crucible and molybdenum oxide and the mass of crucible:
     Mass of molybdenum oxide = 39.84 – 38.26 = 1.58g 

We can now compute for the mass of oxygen O by subtracting the mass of molybdenum from the mass of molybdenum oxide:
     Mass of oxygen in molybdenum oxide = 1.58 – 1.26 = 0.32g O

To convert mass to moles, we use the molar mass of each element.
     1.26 g Mo * 1 mol Mo / 95.94 g Mo = 0.0131 mol Mo
     0.32 g O * 1 mol O / 15.999 g O = 0.0200 mol O

0.0131 mol is the smallest number of moles. We divide each mole value by this number:
     0.0131 mol Mo / 0.0131 = 1
     0.0200 mol O / 0.0131 = 1.53

Multiplying these results by 2 to get the lowest whole number ratio,
     0.0131 mol Mo / 0.0131 = 1 * 2 = 2
     0.0200 mol O / 0.0131 = 1.5 * 2 = 3
Thus, we can write the empirical formula as Mo2O3.
5 0
3 years ago
Read 2 more answers
ANSWER QUICK PLEASE ILL GIVE BRAINLIEST AND 50 POINTS
yawa3891 [41]

Answer:

Single replacement and Zinc Sulfate

the 2nd one is double replacement and potassium nitrate

5 0
2 years ago
Read 2 more answers
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