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VashaNatasha [74]
3 years ago
6

What must be done to the following half-reactions before they can be added together?Mn (s) → Mn 2+ (aq) + 2e − Fe 3+ (aq) + 3e −

→ Fe (s)Double the Mn half-reaction and triple the Fe half-reaction.Add H+ ions to the left-side of the Mn reaction.Triple the Mn half-reaction and double the Fe half-reaction.Double the Mn half-reaction.none of the above
Chemistry
1 answer:
Mrrafil [7]3 years ago
4 0

Answer:

Triple the Mn half reaction and double the Fe half reaction

Explanation:

Because...we have to balance the number of electrons(e)...which will be eliminated from the equations and they will be combined

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Water flows from the bottom of a large tank where the pressure is 100 psig through a pipe to a turbine which produces 5.82 hp. T
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Explanation:

Bernoulli equation for the flow between bottom of the tank and pipe exit point is as follows.

   \frac{p_{1}}{\gamma} + \frac{V^{2}_{1}}{2g} + z_{1} = \frac{p_{2}}{\gamma} + \frac{V^{2}_{2}}{2g} + z_{2} + h_{f} + h_{t}

    \frac{(100 \times 144)}{62.43} + 0 + h[tex] = [tex]\frac{(50 \times 144)}{(62.43)} + \frac{(70)^{2}}{2(32.2)} + 0 + 40 + 60

                          h = \frac{(50 \times 144)}{(62.43)} + \frac{(70)^{2}}{2(32.2)} + 40 + 60 - \frac{(100 \times 144)}{(62.43)}

                            = 60.76 ft

Hence, formula to calculate theoretical power produced by the turbine is as follows.

                                 P = mgh

                                     = 100 \times 60.76

                                     = 6076 lb.ft/s

                                     = 11.047 hp

Efficiency of the turbine will be as follows.

                \eta_{t} = \frac{P_{actual}}{P_{theoretical}} × 100%

                                = \frac{5.82}{11.047} \times 100%                      

                                = 52.684%

Thus, we can conclude that the efficiency of the turbine is 52.684%.

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