Answer:
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Explanation:
The question is incomplete , complete question is :
Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrated (undiluted) standard solution for which you measured the absorbance. Use 3 significant figures. Molarity (μmol/L) =31.5
Given: [TZ] = 0.5461 mol/L
Answer:
The concentration of TZ solution in μmol/L is 546 μmol/L
Explanation:
Molarity of the TZ solution = 0.5461 mol/L
This means that 0.5461 moles of TZ are present in 1 L of solution.
Moles of TZ = 0.5461 mol
So, the concentration of TZ solution in μmol/L is :
546.1 μmol/L ≈ 546 μmol/L
Sorry, Cant really tell how to differentiate the students and trial times
35.9g x 1 mol/ 2.016g x 22.4 L/ 1 mol= 398.89 L
A fluorine atom has seven valence electrons. ... Carbon will then have five valence electrons (its four and the one its sharing with fluorine). Covalently sharing two electrons is also known as a “single bond.” Carbon will have to form four single bonds with four different fluorine atoms to fill its octet.