Answer:
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Step-by-step explanation:
A 6000-seat theater has tickets for sale at $26 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $185,400?
Let
x = number of tickets sold for $26
y = number of tickets sold for $40
x + y = 6000
x = 6000 - y
$26 × x + $40 × y= $185, 400
26x + 40y = 185400
Substitute
26(6000 - y) + 40y = 185400
156000 - 26y + 40y = 185400
Collect like terms
- 26y + 40y = 185400 - 156000
14y = 29400
y = 29400/14
y = 2100 tickets
x = 6000 - y
x = 6000 - 2100
x = 3900 tickets
Hence
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
I think it’s 6
I did 32-26 and got it
That’s all I got
10 cars and 10 trains in 100 hours
it approximately take him 10 hours to build one car and one train how 6+4=10 how many times can 10 go into 100 10 times hope this helps a little
The range for the data given is 11
Halving-reduce by half or think what is fifty% of the number or divide by two
doubling-add the number you got to the same number or multiply by two
Halving Ex.:6/2=3
Doubling ex.: 9+9=18 or 6*2=12
