Question

The population of a strain of bacteria doubles in a culture. At noon there were 80 bacteria present and by 4:00 PM there were 20 480 bacteria. Determine algebraically the doubling period. Hint: You DO NOT need to use systematic trials.

Answer 1

Answer:

t = 1/2 hour

Step-by-step explanation:

20480 = 80$x^{t }$

20480 = 80$x^{4 }$

20480/80  =  $x^{4 }$

256 =  $x^{4 }$

x = 4

doubling period

2 = $4^{t}$

t = 1/2 hour