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Sergio039 [100]
3 years ago
8

Please help. (science question)

Chemistry
2 answers:
dybincka [34]3 years ago
8 0

Answer:Hope this helps :) if so pleas could you mark brainliest:) enjoy!

Explanation:

The cycle of water erosion has been here since forever thanks to the rain rivers, ponds lakes, the sea and the ocean because it first starts off with the rain then the rain fills up the lakes and pond and start rivers and the rivers lead to the sea and ocean and from there the water evaperates then it rains again and the lakes and ponds help with the evaporation.

FinnZ [79.3K]3 years ago
6 0

Answer:water  erodes the earth by passing over rock and thinngs many times, as in a river, the water slowly washes away the rock turning it into sediment or silt.

Explanation:

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<u>Answer:</u> The maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of p-toluidine hydrochloride solution = 0.167 M

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Putting values in above equation, we get:

0.167M=\frac{\text{Moles of p-toluidine hydrochloride}\times 1000}{70}\\\\\text{Moles of p-toluidine hydrochloride}=\frac{0.167\times 70}{1000}=0.0117mol

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\text{p-toluidine hydrochloride}+\text{Acetic anhydride}\rightarrow \text{N-acetyl-p-toluidine}

By Stoichiometry of the reaction:

1 mole of p-toluidine hydrochloride produces 1 mole of N-acetyl-p-toluidine

So, 0.0117 moles of p-toluidine hydrochloride will produce = \frac{1}{1}\times 0.0117=0.0117mol of N-acetyl-p-toluidine

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of N-acetyl-p-toluidine = 149.2 g/mol

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0.0117mol=\frac{\text{Mass of N-acetyl-p-toluidine}}{149.2g/mol}\\\\\text{Mass of N-acetyl-p-toluidine}=(0.0117g/mol\times 149.2)=1.7g

Hence, the maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.

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