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vladimir1956 [14]
3 years ago
14

can someone solve me some papers I don't have time and I need to submit today please I will make you brilliant ​

Chemistry
1 answer:
dem82 [27]3 years ago
6 0

Answer:

submit the papers onto this platform and we will try to help out.

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If a car travels 400.0 meters in 20.0 seconds, how fast is it going?<br> m/s<br> Please help me
Viefleur [7K]

Answer:

20m/s.

Explanation:

8 0
3 years ago
The National Weather Service routinely supplies atmospheric pressure data to help pilots set their altimeters. The units the NWS
pashok25 [27]

Answer:

d. 103.3

Explanation:

In the given question, the National Weather Service routinely supplies atmospheric pressure data to help pilots set their altimeters. And the units of atmospheric pressure used for reporting the atmospheric pressure data are inches of mercury. For a barometric pressure of 30.51 inches of mercury, we can calculate the pressure in kPa as follow:

In principle, 3.386 kPa is equivalent to the atmospheric pressure of 1 inch of mercury. Thus, 30.51 inches of mercury is equivalent to 30.51 in *(3.386 kPa/1 in) = 103.307 kPa.

Therefore, a barometric pressure of 30.51 inches of mercury corresponds to _____103.3_____ kPa.

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3 years ago
Role and significance of guassion or normal distribution?
kkurt [141]
Normal my guy!!!!!!!!!
5 0
3 years ago
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Work done after rutherford's gold foil experiment demonstrated that the nucleus contained ________.
shutvik [7]
Protons and neutrons

hope this helps 
5 0
3 years ago
If the pressure on a gas sample is tripled and the absolute temperature is quadrupled, by what factor will the volume of the sam
antoniya [11.8K]

Answer:

b. 4/3

Explanation:

Given data

  • Initial pressure: P₁
  • Initial volume: V₁
  • Initial temperature: T₁
  • Final pressure: P₂ = 3 P₁
  • Final volume: V₂
  • Final temperature: T₂ = 4 T₁

We can find by what factor will the volume of the sample change using the combined gas law.

\frac{P_{1}.V_{1}}{T_{1}} =\frac{P_{2}.V_{2}}{T_{2}}\\\frac{P_{1}.V_{1}}{T_{1}} =\frac{3P_{1}.V_{2}}{4T_{1}}\\V_{1} =\frac{3V_{2}}{4}\\V_{2}=4/3 V_{1}

7 0
3 years ago
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