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topjm [15]
3 years ago
9

Please help need fast answer please thank you

Chemistry
1 answer:
Tomtit [17]3 years ago
4 0

Answer:

B

Explanation:

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A(n)
alex41 [277]
It should be scientific law since a hypothesis is like a prediction and a theory could be used to explain something although it might not be true. There’s many theories just to explain one thing. So it should be scientific law
8 0
3 years ago
What is the final pressure (expressed in atm) of a 3.05 L system initially at 724 mm Hg and 298 K, that is compressed to a final
maksim [4K]

Hey there!:

V1 = 3.05 L

V2 = 3.00 L

P1 = 724 mmHg

P2 = to be calculated

T1 = 298 K

T2 = 273 K

Therefore:

P1*V1  / T1  = P2*V2 / T2

P2 = ( P1*V1 / T1  )   * T2 / V2

P2 = 724 * 3.05 * 273 / 298 * 3.00

P2 = 602838.6 / 894

P2 = 674.31 mmHg

1 atm ----------- 760 mmHg

atm ------------- 674.31 mHg

= 674.31 * 1 / 760

= 0.887 atm

Hope this helps!

5 0
4 years ago
Which of the following examples best demonstrates kinetic energy?
Vlada [557]
Answer:-

Thanks for not describing your question well enough
4 0
3 years ago
A compound has a mass percentage of 53.46% C, 6.98% H, and 39.56% O. What is the empirical formula for this compound
Lubov Fominskaja [6]

Answer:

The empirical formula is: C₂H₃O

Explanation:

The empirical formula, also known as the “minimum formula”, is the simplest expression to represent a chemical compound and indicates the elements that are present and the minimum integer ratio between its atoms.

The percentage composition is the percentage by mass of each of the elements present in a compound.

Having 100 g of the compound as a base, it is possible to express the percentages in grams. That is, assuming you have 100 g of the compound, you have 53.46 g of  C , 6.98 g of  H , and 39.56 g of  O.

Taking into account the molecular mass of each substance, the number of relative atoms of each chemical element is calculated:

C: 53.46 g *\frac{1 mol}{12.01 g } = 4.45 moles

H:6.98 g *\frac{1 mol}{1.01 g } = 6.91 moles

O:39.56 g *\frac{1 mol}{16g } = 2.47 moles

Now you divide each value obtained by the least of them:

C: \frac{4.45 moles}{2.47 moles}=  1.80

H:\frac{6.91 moles}{2.47 moles}= 2.8

O:\frac{2.47 moles}{2.47 moles}=1

Decimals approach the nearest integer, then:

C: 2

H: 3

O: 1

Therefore <u><em>the empirical formula is: C₂H₃O</em></u>

5 1
3 years ago
Which gas property in the chart above is extensive and cannot be used to identify the gas?
zimovet [89]

Answer:

gas

Explanation:

gas cant be aditanified as a gas if this is not right i am so sorry.

4 0
3 years ago
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