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ludmilkaskok [199]
2 years ago
15

Match the action to the effect on the equilibrium position for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g). (3 points)

Chemistry
1 answer:
AleksandrR [38]2 years ago
5 0

Answer:

1. Adding hydrogen gas, b. shift to the right
2. Adding a catalyst, c. No effect
3. Decreasing the pressure, a. shift to the left

Explanation:

Hydrogen gas can be rewritten as H2. Whenever you add something to an equilibrium expression, it will shift to whichever side does not have this. So, since the reactant side has 3 moles of H2, adding more H2 to the reaction will shift to the products side, since there is no H2 there.


Adding a catalyst has no effect on equilibrium reactions.

When decreasing the pressure, equilibrium will shift to the side with the greater number of moles of gas. In this case, there are 4 moles of gas on the left, and 2 on the right, so it would shift to the left.

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How many moles of hcl will react when you start with 1 L of a 0.5 M HCl aqueous solution?
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1L of 0.5M HCl contains 0.5mol of HCl which can react.

This can be found by the fact that
molarity is defined as the number of moles of a substance per Liter of solution. That means that 0.5M of HCl can be thought of as 0.5moles of HCl per liter of solution.

In general to find the number of moles of substance in a solution using the molarity all you do is multiply the molarity by the volume of the solution (in liters).

I hope this helps. Let me know if anything is unclear.
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How many moles of oxygen are in 1 mole of Fe(NO3)3?
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Which type of mixture is formed when one substance dissolves into another and fills the spaces between other kinds of molecules?
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4 years ago
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4 0
3 years ago
Milk of magnesia is often taken to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 te
Igoryamba

Answer:

8.61 mL of the HCl solution

Explanation:

The reaction that takes place is:

  • 2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O

From the given mass of Mg(OH)₂, we can calculate <u>the moles of HCl that are neutralized</u>:

  • 4x10² mg = 400 mg = 0.400g
  • 0.400g Mg(OH)₂ ÷ 58.32g/1mol = 6.859*10⁻³ mol Mg(OH)₂
  • 6.859*10⁻³ mol Mg(OH)₂ * \frac{1molHCl}{1molMg(OH)_{2}} = 3.429x10⁻³ mol HCl

Finally, to calculate the volume of an HCl solution, we need both the moles and the concentration. We can <u>calculate the concentration using the pH value</u>:

  • pH = -log[H⁺]
  • 1.4 =  -log[H⁺]
  • 10^{-1.4} = [H⁺]
  • 0.0398 M = [H⁺] = [HCl]  *Because HCl is a strong acid*

Thus, the volume is:

  • 0.0398 M = 3.429x10⁻³mol HCl / Volume
  • Volume = 8.616x10⁻³ L = 8.62 mL

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4 years ago
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