Given that,
s = √(2t + 1)
Time, t = 4 s
Acceleration , a = ??
Since,
Acceleration = velocity / time
Velocity = distance/ time
Acceleration = distance/ time²
s/t² = √(2t+1)/t²
putting t = 4 sec, we have
a = √(2*4+1)/4²
a = √(5)/16
a= 0.139 ft/s²
Therefore, acceleration of the given particle will be 0.139 feet/ second².
It is derived because you can not determine the rate of speed it will always be because any amount of sheer force can be applied to it.
Answer:
First answer to the first question is Two people pulling a rope with the same force in a opposite direction. The other one would be 2.72N
Explanation:
Hope this helps you :)
How about a carousel (merry go round).
For any one horse or rider, Speed is constant but direction keeps changing, so velocity does too.