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Georgia [21]
3 years ago
10

If this decay has half-life of 2 years, how many years would it take for 10.8 g Protactinium-231 to remain given an initial mass

of 86.3 g?

Physics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

Time = 6 years

Explanation:

First, we will calculate the no. of half life periods required to reduce the mass of Protactinium to the given value:

m' = \frac{m}{2^{n} } \\\\2^n = \frac{m}{m'}

where,

n = no. of half-life periods = ?

m = initial mass = 86.3 g

m' = remaining mass = 10.8 g

Therefore,

2^n = \frac{86.3\ g}{10.8\ g}\\\\2^n = 8\\2^n = 2^3

Since the bases are the same. Therefore equating powers:

n = 3

Now we calculate the time:

Time = (n)(Half-Life)\\Time =(3)(2\ years)

<u>Time = 6 years</u>

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