Question

Two 30 uC charges lie on the x-axis, one at the origin and the other at 9 m. A third point is located at 27 m. What is the potential at this third point relative to infinity? (The value of k is 9.0 x10^9 N-m^2/C^2.) A) 750 V B) 2500 V C) 2000 V D) 3000 V

Answer 1

Answer:

25000 V

Explanation:

The formula for potential is

V = Kq/r

Potential at B due to the charge placed at origin O

V1 = K q / OB

$V_{1}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{27}$

V1 = 10000 V

Potential at B due to the charge placed at A

V2 = K q / AB

$V_{2}= \frac{9 \times 10^{9} \times 30 \times 10^{-6}}{18}$

V2 = 15000 V

Total potential at B

V = V1 + V2 = 10000 + 15000 = 25000 V