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3 years ago

What happens to water when it changes Into ice?

2 answers:

6 0

Point out that when water freezes, the water molecules have slowed down enough that their attractions arrange them into fixed positions. Water molecules freeze in a hexagonal pattern and the molecules are further apart than they were in liquid water. Note: The molecules in ice would be vibrating.

devlian [24]3 years ago

3 0

It is converted into solid matte

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Now assume that the mass of object 1 is 2m, while the mass of object 2 remains m. If the collision is elastic, what are the fina

Artemon [7]

Answer:

(v₁, v₂) = [(v/3), (4v/3)]

(v₁, v₂) = (v, 0)

Explanation:

In elastic collisions, the momentum and kinetic energy is usually conserved.

The momentum before collision = momentum after collision

And

Kinetic energy before collision = Kinetic energy after collision

Momentum of object 1 before collision = (2m)v = 2mv

Momentum of object 2 before collision = (m)(0) = 0

Momentum of object 1 after collision = (2m)(v₁) = 2mv₁

Momentum of object 2 after collision = (m)(v₂) = mv₂

So, we have

2mv = 2mv₁ + mv₂

2v = 2v₁ + v₂

v₂ = 2v - 2v₁ (eqn 1)

Kinetic energy of object 1 before collision = (1/2)(2m)(v²) = mv²

Kinetic energy of object 2 before collision = (1/2)(m)(0²) = 0

Kinetic energy of object 1 after collision = (1/2)(2m)(v₁²) = mv₁²

Kinetic energy of object 2 after collision = (1/2)(m)(v₁²) = (mv₂²/2)

So, we have,

mv² = mv₁² + (mv₂²/2)

v² = v₁² + (v₂²/2)

2v² = 2v₁² + v₂² (eqn 2)

Substitute (v₂ = 2v - 2v₁) from (eqn 1) into (eqn 2)

2v² = 2v₁² + (2v - 2v₁)²

2v² = 2v₁² + 4v² - 8vv₁ + 4v₁²

6v₁² - 8vv₁ + 2v² = 0

6v₁² - 6vv₁ - 2vv₁ + 2v² = 0

6v₁(v₁ - v) - 2v(v₁ - v) = 0

(6v₁ - 2v)(v₁ - v) = 0

6v₁ = 2v or v₁ = v

v₁ = (v/3) or v₁ = v

If v₁ = (v/3)

From (eqn 1)

v₂ = 2v - 2v₁

v₂ = 2v - 2(v/3)

v₂ = 2v - (2v/3)

v₂ = (4v/3)

If v₁ = v,

From eqn 1,

v₂ = 2v - 2v₁

v₂ = 2v - 2v = 0

(v₁, v₂) = [(v/3), (4v/3)]

(v₁, v₂) = (v, 0)

8 0

3 years ago

What is the part of the earth that you walk on called?

olasank [31]

The part of the Earth that you walk on is called the CRUST.

6 0

4 years ago

a body starts from rest and accelerates uniformly at 5ms‐2. Calculate the time taken by the body to cover a distance of 1km

mixas84 [53]

The body will take 20 seconds to cover a distance of 1000 m i.e. 1 km

7 0

3 years ago

Read 2 more answers

Automobile air bags use the decomposition of sodium azide as their sources of gas for rapid inflation, represented in the reacti

NeTakaya

Answer : The mass of $NaN_3$ required is 71.175 grams.

Explanation :

To calculate the moles of nitrogen gas, we use the equation given by ideal gas :

PV = nRT

where,

P = Pressure of nitrogen gas = 763 torr

V = Volume of the nitrogen gas = 40.0 L

n = number of moles of gas = ?

R = Gas constant = $62.364\text{ L.torr }mol^{-1}K^{-1}$

T = Temperature of helium gas = $25^oC=273+25=298K$

Putting values in above equation, we get:

$763torr\times 40.0L=n\times 62.364\text{ L.torr }mol^{-1}K^{-1}\times 298K\\\\n=1.642mol$

Now we have to calculate the moles of $NaN_3$ .

The balanced chemical reaction is:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced chemical reaction, we conclude that

As, 3 moles of $N_2$ produced from 2 moles $NaN_3$

So, 1.642 moles of $N_2$ produced from $\frac{2}{3}\times 1.642=1.095$ moles $NaN_3$

Now we have to calculate the mass of $NaN_3$ .

Molar mass of $NaN_3$ = 65 g/mol

$\text{Mass of }NaN_3=\text{Moles of }NaN_3\times \text{Molar mass of }NaN_3$

$\text{Mass of }NaN_3=1.095mole\times 65g/mole=71.175g$

Therefore, the mass of $NaN_3$ required is 71.175 grams.

5 0

4 years ago

a person brings his face close to a mirror . h e finds that the image of his face is magnified write the name of the mirror used

DIA [1.3K]

Answer:

Spherical concave mirrors

Explanation:

Like spherical convex mirrors, spherical concave mirrors have a focus. If the object is closer to the mirror than the focal point is, the image will be virtual, like we talked about before for the plane mirror and the convex mirror.

Concave mirrors, on the other hand, can have real images. If the object is further away from the mirror than the focal point, the image will be upside-down and real---meaning that the image appears on the same side of the mirror as the object.

The closer the object comes to the focal point (without passing it), the bigger the image will be.

You can try this yourself by looking into the concave side of a shiny spoon. If you look into the spoon while holding it at arm’s length, you’ll see an extremely magnified, upside-down image of your face. But as you bring the spoon closer to your eyes, the image will get bigger and bigger.

- Hope this helps! <3

5 0

3 years ago