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Maru [420]
2 years ago
7

Answer for brainlest plssss

Mathematics
2 answers:
Misha Larkins [42]2 years ago
7 0

Answer:

\displaystyle d)  36 \:  {in}^{2}

Step-by-step explanation:

the polygon can be separated in two parts

  1. rectangle
  2. triangle

let's figure out the area of the rectangle

recall that,

  • \displaystyle A_{ \rm rect} =l \times w

given that,

  • l=9
  • w=3

thus substitute:

  • \displaystyle A_{ \rm rect} =9\times 3

simplify multiplication:

  • \displaystyle A_{ \rm rect} =27

let's figure out the area of the triangle

remember that,

\displaystyle A_{ \rm triangle} = \frac{1}{2} \times  b\times h

substitute the value of b and h:

\displaystyle A_{ \rm triangle} = \frac{1}{2} \times  9\times 2

reduce fraction:

\displaystyle A_{ \rm triangle} =    9

now the area of the polygon would be the total area of the rectangle and triangle thus

\displaystyle A_{ \rm polygon} =    27 + 9

simplify addition:

\displaystyle A_{ \rm polygon} =    36

hence our answer is D)

AysviL [449]2 years ago
6 0
The answer is in the photo

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Soloha48 [4]
Angle a is directly opposite from a 40 degree angle, so a=40. Then we can find b since the sum of the angles of all triangles is 180 and there is a right angle in there along with angle a:
180=90+40+b
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Last, to find c we just notice that it is supplementary with an angle of measure 65, so:
c+65=180
c=115

So our angles are a=40, b=50, c=115.
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3 years ago
Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
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Hope this helps!
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3 years ago
The area of a right triangle is given by the expression:
lorasvet [3.4K]

The expression that models the length of the second leg of the triangle is <u>2x - 3.</u>

<u><em>Recall</em></u>:

The area of a triangle = \frac{1}{2} bh

<em><u>Given</u></em>:

Area of triangle = \frac{1}{2} (6x^2 - 7x - 3)

Length of one of the legs = 3x + 1

Therefore, it means that multiplying both legs should give us:

6x^2 - 7x - 3

To find the expression that models the other leg, divide 6x^2 - 7x - 3 by 3x + 1:

  • <em>Thus</em>:

\frac{6x^2 - 7x - 3}{3x - 1}

  • Factorize the numerator

\frac{6x^2 - 2x - 9x - 3}{3x - 1}\\\\\frac{2x(3x - 1) - 3(3x - 1)}{3x - 1}\\\\\frac{(2x- 3)(3x - 1)}{3x - 1}

  • Simplify

\frac{(2x- 3)(3x - 1)}{3x - 1} = 2x- 3

Therefore, the expression that models the length of the second leg of the triangle is <u>2x - 3.</u>

<u></u>

<u></u>

Learn more here:

brainly.com/question/20712284

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i think soooo

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Step-by-step explanation:

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