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Juli2301 [7.4K]
2 years ago
14

scrapers are used to haul dirt from a borrow pit to the cap of a landfill. the estimated cycle time for the scrapers is 9.5 minu

tes. The scrapers carry 10 cubic yards of soil per trip . using a system efficiency of 45 minutes per hour and producitivity factor of determine the number of labor hours to haul 1 cubic yard of dirt. each scraper require one operator
Engineering
1 answer:
ladessa [460]2 years ago
7 0
Answer is: 12.8 because when you multiply it by the 2nd power of 8 then the scraper equals to be 12.8 in height and that’s how much each scraper requires to operate :)
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The basic barometer can be used to measure the height of a building. If the barometric readings at the top and the bottom of a b
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Answer:

230.51 m

Explanation:

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Pt = 675 mmHg

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dP = p * g * H = (13600)*(9.81)*(20/1000) = 2668.320 Pa

Calculate Height of building as dP is same for any medium of liquid

dP = p*g*H = 2668.320

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3 years ago
Steam at 75 kPa and 8 percent quality is contained in a spring-loaded piston–cylinder device, as shown in Figure, with an initia
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The heat transferred to and the work produced by the steam during this process  is 13781.618 kJ/kg

<h3>​How to calcultae the heat?</h3>

The Net Change in Enthalpy will be:

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= 1/2 x ( 75 + 225) x (5 - 2)

W = 450 KJ

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6 0
1 year ago
Will mark brainliest!
sukhopar [10]

Ethics in production is a subset of business ethic that is meant to ensure that the production function or activities are not damaging to the consumer or the society. Like other ethics there is a certain code of conduct or standards to be followed, however ensuring that the ethics are complied with is often difficult.

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6 0
3 years ago
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Consider a resistor made of pure silicon with a cross-sectional area pf 0.5 μm2, and a length of 50 μm. What is the resistance o
lukranit [14]

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Explanation:

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Based on these considerations, we found that at room temperature, pure silicon resistivity can be approximated as 2.1. 10⁵  Ω  cm.

The resistance R of a given resistor, is expressed by the following formula:

R = ρ L / A

Replacing by the values for resistivity, L and A, we have

R = 2.1. 10⁵ Ω  cm. (10⁴ μm/cm). 50 μm/ 0.5 μm2

R = 2.1. 10¹¹ Ω

Assuming that we can apply Ohm´s Law, the current that would pass through this resistor for an applied voltage of 5 V, is as follows:

I = V/R = 5 V / 2.1.10¹¹ Ω = 2.38. 10⁻¹¹ A= 24 pA

7 0
3 years ago
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Answer:

Hearing protection would be your answer!

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