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Korvikt [17]
3 years ago
14

Select all the compounds below that contain ionic bonds. (Cross out/delete compounds that are not ionic.)

Chemistry
1 answer:
kow [346]3 years ago
7 0
It’s 2 but maybe 5 but it’s probably 2 hope it helps so yeah I and
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Newtons second law of motion states that
insens350 [35]

Answer:

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force,

Explanation:

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3 years ago
Which statements describe the elements? Which ones are true and which ones are false?
Alchen [17]

Answer:

Explanation:

Uma declaração verdade é identificada pelo de ela afirmar a verdade diferente das outras opções

8 0
3 years ago
Calculate the moles of FeFe in 1.17×10221.17×1022atoms of FeFe.
Ivenika [448]

Answer:

The number of moles of Fe in 1.17*10^22 atoms Fe is 0.0194 moles

Explanation:

Step 1: Data given

Number of atoms of Fe = 1.17 * 10^22 atoms

Number of Avogadro = 6.022 *10^23

Step 2: Calculate number of moles Fe

Moles Fe = atoms Fe / number of Avogadro

Moles Fe = 1.17*10^22 atoms / 6.022*10^23 / moles

Moles Fe = 0.0194 moles

The number of moles of Fe in 1.17*10^22 atoms Fe is 0.0194 moles

4 0
3 years ago
How many moles of C6H12O6 will be produced if 22 grams of CO2 are reacted
SSSSS [86.1K]

Answer:

60 grams

Explanation:

We have the balanced equation (without state symbols):

6

H

2

O

+

6

C

O

2

→

C

6

H

12

O

6

+

6

O

2

So, we would need six moles of carbon dioxide to fully produce one mole of glucose.

Here, we got  

88

 

g

of carbon dioxide, and we need to convert it into moles.

Carbon dioxide has a molar mass of  

44

 

g/mol

. So here, there exist

88

g

44

g

/mol

=

2

 

mol

Since there are two moles of  

C

O

2

, we can produce  

2

6

⋅

1

=

1

3

moles of glucose  

(

C

6

H

12

O

6

)

.

We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass.

Glucose has a molar mass of  

180.156

 

g/mol

. So here, the mass of glucose produced is

1

3

mol

⋅

180.156

 

g

mol

≈

60

 

g

to the nearest whole number.

So, approximately  

60

grams of glucose will be produced.

5 0
3 years ago
Balancing equations
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Make sure you numbers with variable are on one side and the numbers 

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4 years ago
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