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Deffense [45]
3 years ago
6

Why is it necessary to heat the hydrate gently at first and then more strongly only after most of the water has been driven off

Chemistry
1 answer:
xxTIMURxx [149]3 years ago
5 0

Answer:

To avoid spattering

Explanation:

If we are heating a hydrate to drive off the water of crystallization, we must initially heat the hydrate gently, at a lower temperature and then more strongly only after most of the water has been driven off in order to to prevent spattering.

Since we obtain the amount of water by the mass difference, Spattering  decreases the mass of water obtained and ultimately results in a lower percent of water being calculated for the hydrate.

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2 is the valancy of alkine

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Which of the following statements explain why the van der Waals equation must be used to describe real gases? X. interactions be
8090 [49]

Answer:

Statements Y and Z.

Explanation:

The Van der Waals equation is the next one:

nRT = (P + \frac{an^{2}}{V^{2}})(V -nb) (1)

The ideal gas law is the following:

nRT = PV (2)

<em>where n: is the moles of the gas, R: is the gas constant, T: is the temperature, P: is the measured pressure, V: is the volume of the container, and a and b: are measured constants for a specific gas.  </em>

As we can see from equation (1), the Van der Waals equation introduces two terms that correct the P and the V of the ideal gas equation (2),<u> by the incorporation of the intermolecular interaction between the gases and the gases volume</u>. The term an²/V² corrects the P of the ideal gas equation since the measured pressure is decreased by the attraction forces between the gases. The term nb corrects the V of the ideal gas equation, <u>taking into account the volume occuppied by the gas in the total volume, which implies</u> a reduction of the total space available for the gas molecules.          

So, the correct statements are the Y and Z: the non-zero volumes of the gas particles effectively decrease the amount of "empty space" between them and the molecular attractions between gas particles decrease the pressure exerted by the gas.            

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5 0
3 years ago
Help me ASAP PLS
n200080 [17]

Answer:

18 g

Explanation:

We'll begin by converting 500 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

500 mL = 500 mL × 1 L / 1000 mL

500 mL = 0.5 L

Next, we shall determine the number of mole of the glucose, C₆H₁₂O₆ in the solution. This can be obtained as follow:

Volume = 0.5 L

Molarity = 0.2 M

Mole of C₆H₁₂O₆ =?

Molarity = mole / Volume

0.2 = Mole of C₆H₁₂O₆ / 0.5

Cross multiply

Mole of C₆H₁₂O₆ = 0.2 × 0.5

Mole of C₆H₁₂O₆ = 0.1 mole

Finally, we shall determine the mass of 0.1 mole of C₆H₁₂O₆. This can be obtained as follow:

Mole of C₆H₁₂O₆ = 0.1 mole

Molar mass of C₆H₁₂O₆ = (12×6) + (1×12) + (16×6)

= 72 + 12 + 96

= 180 g/mol

Mass of C₆H₁₂O₆ =?

Mass = mole × molar mass

Mass of C₆H₁₂O₆ = 0.1 × 180

Mass of C₆H₁₂O₆ = 18 g

Thus, 18 g of glucose, C₆H₁₂O₆ is needed to prepare the solution.

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What's what's the Lewis structure for 2H2O ​
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Lewis Structure:

H -- O -- H (bent, Oxygen has 2 lone pairs)

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dose this make any sense...??

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C. Warm ocean currents bring warmer temperatures to coastal cities

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