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telo118 [61]
3 years ago
10

While elements and compounds can both be classified as pure substances because they have distinct properties and composition, __

________ cannot be decomposed further. A) compounds B) elements C) formulas D) molecules
Chemistry
2 answers:
Tresset [83]3 years ago
4 0
Elements as they are fundamental (one single hydrogen atom is still an element
makkiz [27]3 years ago
3 0
Elements or answer b
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I really need help with this problem.
Aleksandr [31]

Answer:

.371 mole of NaCl

Explanation:

Na Cl Mole weight = 22.989   + 35.45 = 58.439 g/mole

21.7 g / 58.439 g/mole = .371 mole

8 0
1 year ago
Calculate the temperature change that occurs when 254 cal of heat are added to 24 g of water
Tomtit [17]
Hey

Calculate the temperature change that occurs when 254 cal of heat are added to 24 g of water
answer:  800
3 0
3 years ago
What is the mass of 2.40 moles of magnesium chloride, mgcl2
LiRa [457]

Hey there!

MgCl₂

Find molar mass of magnesium chloride.

Mg: 1 x 24.305

Cl: 2 x 35.453

--------------------  

          95.211 grams

One mole of magnesium chloride has a mass of 95.211 grams.

We have 2.40 moles.

2.40 x 95.211 = 228.5

To 3 sig figs this is 229.

The mass of 2.40 moles of magnesium chloride is 229 grams.

Hope this helps!

4 0
2 years ago
Please tell if my answer is right or wrong.
xxTIMURxx [149]
Change the places of 'acts against the motion of an object' and 'causes an object to change speed or direction'
5 0
3 years ago
A solution is prepared by adding 0.0231moles of H3O+ ions to 3.33L of water. What is the pH of this solution
MrMuchimi

Answer:

2.15

Explanation:

For this question, we have to remember the <u>pH formula</u>:

pH~=~-Log[H_3O^+]

By definition, the pH value is calculated when we do the -Log of the concentration of the <u>hydronium ions</u> (H_3O^+). So, the next step is the calculation of the <u>concentration</u> of the hydronium ions. For this, we have to use the <u>molarity formula</u>:

M=\frac{mol}{L}

We already know the number of moles (0.0231 moles) and the volume (3.33 L). So, we can plug the values into the molarity formula:

M=\frac{0.0231~moles}{3.33~L}=0.00693~M

With this value, now we can calculate the pH value:

pH~=~-Log[0.00693~M]~=~2.15

<u>The pH would be 2.15</u>

I hope it helps!

8 0
2 years ago
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