2 because that’s correct I I I I I I I I I I I I I I I I I I I
The total energy equation would be Kinetic energy+Potential energy
Answer:

Explanation:
Time to mow 1 lawn by Wilma is 80 minutes
so work done in 1 minute by Wilma is given as
Similarly Rocky mow same lawn in 120 minute
so work done in 1 minute by Rocky is given as

now we know that they both worked by "t" time
so total work performed by them

they both mow 2 lawns then it is given as


Answer:
A) 80 N
Explanation:
The closer the particles get, the stronger the Coulomb force, which elongates choices C and D. The Coulomb force is inversely proportional to the distance squared. If the distance is cut in half, the force is multiplied by the reciprocal of (1/2)^2, which is 4. Multiplying it out, 20 times 4 is 80 N.
Answer:
Total work done in expansion will be 
Explanation:
We have given pressure P = 2.10 atm
We know that 1 atm 
So 2.10 atm 
Volume is increases from 3370 liter to 5.40 liter
So initial volume 
And final volume 
So change in volume 
For isobaric process work done is equal to 
So total work done in expansion will be 