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Rudiy27
3 years ago
10

How do people participate in tourism

Physics
1 answer:
Makovka662 [10]3 years ago
5 0
Community participation in tourism helps to uphold the local culture, tradition and indigenous knowledge of the local people. It also helps in conservation of the environment and culture of the local community.
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What is the new pressure of 150 ml of a gas that is compressed to 50 ml when the original pressure was 3.0 atm and the temperatu
Firlakuza [10]

Answer: 9.0 atm

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=3.0atm\\V_1=150mL\\P_2=?mmHg\\V_2=50mL

Putting values in above equation, we get:

3.0\times 150mL=P_2\times 50mL\\\\P_2=9.0atm

Thus new pressure of 150 ml of a gas that is compressed to 50 ml is 9.0 atm

5 0
4 years ago
A constant horizontal F force began to act on the initially immovable body placed on a horizontal surface. After t time the forc
mel-nik [20]

Answer:

The coefficient of friction is (F/(19.6·m)

Explanation:

The given parameters are;

The force applied to the immovable body = F

The time duration the force acts = t

The time the body spends in motion = 3·t

The acceleration due to gravity, g = 9.8 m/s²

From Newton's second law of motion, we have;

The impulse of the force = F × t = m × Δv₁

Where;

Δv₁ = v₁ - 0 = v₁

The impulse applied by the force of friction, F_f is F_f × (3·t - t) =  F_f × (2·t)

Given that the motion of the object is stopped by the frictional force, we have;

The impulse due to the frictional force = Momentum change = m × Δv₂ = F_f × (2·t)

Where;

Δv₂ = v₂ - 0 = v₂

Given that the velocity, v₂, at the start of the deceleration = The velocity at the point the force ceased to  act, v₁, we have;

m × Δv₂ = F_f × (2·t) = m × Δv₁ = F × t

∴ F_f × (2·t) = F × t

F_f = F × t/(2·t) = F/2

The coefficient of dynamic friction, \mu _k = Frictional force/(The weight of the body) = (F/2)/(9.8 × m)

\mu _k = (F/(19.6·m)

The coefficient of friction, \mu _k = (F/(19.6·m)

5 0
3 years ago
HELP PLS MARKING BRANLIST 100 Pts TAKING TEST RN
ladessa [460]

Answer:

-10 m/s

Hope this helps!!!

8 0
3 years ago
Identify the differences between the dfss (design for six sigma) and the dmaic (define, measure, analyze, improve, control) proc
s344n2d4d5 [400]

The difference between the dfss (design for six sigma) and the dmaic (define, measure, analyze, improve, control) processes only lies in the analyzing stage. To further avert problems, DFSS requires market research data, customer complaints about the product, and attempts to rebuild a new product.

The primary distinction is that DMAIC is a technique that emphasizes making changes to the organization's current goods and services.

On the other hand, DFSS strives to create a new, defect-free good or service that satisfies CTQ requirements and results in customer satisfaction.

Design for Six Sigma (DFSS) is an improvement process that aids companies in producing high-quality new goods and services.

The technique tries to satisfy client expectations while making the most of the company's capabilities during the initial development of a process.

A data-driven quality technique called Define, Measure, Analyze, Improve, and Control (DMAIC) is used to enhance processes.

Learn more about DMAIC here brainly.com/question/6352959

#SPJ4

3 0
2 years ago
Two loudspeakers on a concert stage are vibrating in phase. A listener 50.5 m from the left speaker and 26.0 m from the right on
mixer [17]

To solve this problem, it is necessary to apply the concepts related to the constructive interference caused by the wavelengths of the sound traveling in the air.

From the definition of constructive interference we know that

\Delta x = n \lambda \rightarrow \lambda = \frac{\Delta x}{n}

Where

\Delta x = Distance between speakers

n = Integer which represent he number of repetition of the spectrum

\lambda = Wavelength

At the same time the frequency is subject to the form,

f = \frac{v}{\lambda}

Where

v = 343m/s \rightarrow Velocity (of the sound at this case)

From our given values we have to \Delta x is

\Delta x = 50.5m-26m

\Delta x = 24.5m

The wavelength would be subject to the sound spectrum therefore for n = 1,

\lambda = \frac{\Delta x}{n}

\lambda = \frac{24.5}{1}

\lambda = 24.5m

Then the frequency would be,

f = \frac{v}{\lambda}

f = \frac{343}{24.5}

f = 14Hz

For the value of n = 2,

\lambda = \frac{\Delta x}{n}

\lambda = \frac{24.5}{2}

\lambda = 12.25m

Then the frequency would be,

f = \frac{v}{\lambda}

f = \frac{343}{12.25}

f = 28Hz

For n = 3,

\lambda = \frac{\Delta x}{n}

\lambda = \frac{24.5}{3}

\lambda = 8.167m

Then the frequency would be,

f = \frac{v}{\lambda}

f = \frac{343}{12.25}

f = 42Hz

From the frequencies obtained we can identify that the two lowest frequencies that can be heard due to constructive interference are 28Hz and 42Hz

5 0
3 years ago
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