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blondinia [14]
2 years ago
15

A tuning fork vibrating in water with a frequency of 840 Hz produces waves that are 2.5 m long. If a tuning fork vibrating at 50

0 Hz produces the same type of wave in water, what will the wavelength of the waves be?
A) 1.5 m
B) 4.2 m
C) 3.2 m
D) 2.5 m
Physics
1 answer:
IRINA_888 [86]2 years ago
7 0

Answer:

Option B

Explanation:

As we know

Frequency (F) * wavelength (W) = C (speed of light - can also be taken as constant)

Hence,

F1 W1 = C\\F2W2 = C

Or F1W1 = F2W2

Substituting the given values, we get -

840 *2.5 = 500 *XX = 4.2 m

Hence, option B is correct

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Answer:

U=50.96J

Explanation:

The electrostatic potential energy for pair of charge is given by

U=1/4π∈₀×(q₁q₂/r)

Hence for a system of three charges the electrostatic potential energy can be found by adding up the potential energy for all possible pairs or charges.For three equal charges on the corners of an equilateral triangle,the electrostatic potential energy is given by:

U=1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)

U=3×1/4π∈₀×(q²/r)

Substitute given values

So

U=3\frac{1}{4\pi E_{o} }\frac{q^{2} }{r}\\  U=3\frac{1}{4\pi8.85*10^{-12} }\frac{(1.15*10^{-6}C )^{2} }{0.0007m}\\  U=50.96J

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3 years ago
2. What is the speed of a car that travels 73.4 kilometers (km) in 5 hours?
maksim [4K]
Speed =dist./time
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3 years ago
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A very long string (linear density 0.7 kg/m ) is stretched with a tension of 70 N . One end of the string oscillates up and down
rewona [7]

To develop this problem it is necessary to apply the concepts related to Wavelength, The relationship between speed, voltage and linear density as well as frequency. By definition the speed as a function of the tension and the linear density is given by

V = \sqrt{\frac{T}{\rho}}

Where,

T = Tension

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Our data are given by

Tension , T = 70 N

Linear density , \rho = 0.7 kg/m

Amplitude , A = 7 cm = 0.07 m

Period , t = 0.35 s

Replacing our values,

V = \sqrt{\frac{T}{\rho}}

V = \sqrt{\frac{70}{0.7}

V = 10m/s

Speed can also be expressed as

V = \lambda f

Re-arrange to find \lambda

\lambda = \frac{V}{f}

Where,

f = Frequency,

Which is also described in function of the Period as,

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Therefore replacing to find \lambda

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3 years ago
Which bright solar feature is shown in the picture above?
Ghella [55]

Answer : (B) Prominence

Explanation :

A large, glittering and gaseous characteristic which is extending outward from the surface of the sun is called <em>Prominence</em>.

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<em>Corona</em> is a region in the surface of the sun which is the constituent of hot ionized gases (plasma).

The prominence consists of colder plasma and this prominence plasma is much more shining and denser as compared to coronal plasma.

Hence, the correct option is (B) Prominence.

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Yanka [14]

Answer:

Sorry I'm wrong The person above is correct.

I tried.

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