A football is kicked from a tee at 12 m/s at 72° above the horizontal. What is the maximum height of the football
1 answer:
The maximum height is reached when the vertical component of the velocity is zero.
vertical direction:
acceleration: a = -g = -9.81m/s²
velocity: v = -g*t + v₀
position: y = -0.5*g*t² + v₀*t + y₀
For v= 0:
0 = -g*t + v₀ => t = v₀/g
Insert into position equation gives:
y(max) = (-0.5*v₀²/g) + (v₀²/g) + y₀ = (0.5*v₀²/g) + y₀
vertical direction:
acceleration: a = -g = -9.81m/s²
velocity: v = -g*t + v₀
position: y = -0.5*g*t² + v₀*t + y₀
For v= 0:
0 = -g*t + v₀ => t = v₀/g
Insert into position equation gives:
y(max) = (-0.5*v₀²/g) + (v₀²/g) + y₀ = (0.5*v₀²/g) + y₀
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Explanation:
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The weight of the buddy be = 120 kg
The weight of Bubba be = 60 kg
Also, since you and Budda are a distance of 4m to each other, then the length to which both meet buddy will be:
The length of the boat be = 4 m
∴
We can find the center of mass of the system by using the formula: