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gregori [183]
3 years ago
11

A football is kicked from a tee at 12 m/s at 72° above the horizontal. What is the maximum height of the football

Physics
1 answer:
ale4655 [162]3 years ago
6 0
The maximum height is reached when the vertical component of the velocity is zero.

vertical direction:
acceleration: a = -g = -9.81m/s²
velocity: v = -g*t + v₀
position: y = -0.5*g*t² + v₀*t + y₀

For v= 0:
0 = -g*t + v₀ => t = v₀/g 
Insert into position equation gives:
y(max) = (-0.5*v₀²/g) + (v₀²/g) + y₀ = (0.5*v₀²/g) + y₀

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\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}

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