Answer:
λ = 5.656 x 10⁻⁷ m = 565.6 nm
Explanation:
Using the formula of fringe spacing from the Young's Double Slit experiment, which is given as follows:

where,
λ = wavelength = ?
Δx = fringe spacing = 1.6 cm = 0.016 m
L = Distance between slits and screen = 4.95 m
d = slit separation = 0.175 mm = 0.000175 m
Therefore,

<u>λ = 5.656 x 10⁻⁷ m = 565.6 nm</u>
Answer:
The right solution is:
(a) 2.87 eV
(b) 1.4375 eV
Explanation:
Given:
Wavelength,
= 433 nm
Potential difference,
= 1.43 V
Now,
(a)
The energy of photon will be:
E = 
= 
or,
= 
= 
(b)
As we know,
⇒ 
By substituting the values, we get
⇒ 
⇒ 
or,
⇒ 
⇒ 
Sivilculture isis the art and science of managing forests for desired outcomes.
All you would do is for a, 10 times 2 is 20 so it would be 20-dB
For b, 10 times 4 is 40 so it would be 40-dB
<span>For c, 10 times 8 is 80 so it would be 80-dB</span>