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aliya0001 [1]
3 years ago
11

If a toy train has a mass of 1.5 KG and accelerates at a rate of 20 M/S 2 calculate force acting on it?

Physics
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

F = 30 N

Explanation:

Given that,

Mass of a toy train, m = 1.5 kg

The acceleration of the toy-train, a = 20 m/s²

We need to find the force acting on it. We know that, net force acting on an object is given by :

F = ma

Substitute all the values,

F = 1.5 × 20

F = 30 N

Hence, the net force acting on the toy train is equal to 30 N.

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Answer:

Vx = 35 x cos(13deg)

Vy = 35 x sin(13deg) - gt  

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Explanation:

The tiger leaps up, then x and y component of its velocity are:

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Hope this helps!

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v = \omega \sqrt{A^{2} - x^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~`~(1)

where, \omega is the angular frequency, A is the amplitude of the oscillation and x is the displacement of the particle at any instant of time.

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The maximum velocity(\bf{v_{m}}) is

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Divide equation (1) by equation(2).

\dfrac{v}{v_{m}} = \dfrac{\sqrt{A^{2} - x^{2}}}{A}~~~~~~~~~~~~~~~~~~~~~~~~~~~(3)

Given, v = 0.25 v_{m} and A = 15~cm. Substitute these values in equation (3).

&& \dfrac{1}{4} = \dfrac{\sqrt{15^{2} - x^{2}}}{15}\\&or,& A = 14.52~cm

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Letter B

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