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aliya0001 [1]
3 years ago
11

If a toy train has a mass of 1.5 KG and accelerates at a rate of 20 M/S 2 calculate force acting on it?

Physics
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

F = 30 N

Explanation:

Given that,

Mass of a toy train, m = 1.5 kg

The acceleration of the toy-train, a = 20 m/s²

We need to find the force acting on it. We know that, net force acting on an object is given by :

F = ma

Substitute all the values,

F = 1.5 × 20

F = 30 N

Hence, the net force acting on the toy train is equal to 30 N.

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A rigid tank initially contains 3kg of carbon dioxide (CO2) at a pressure of 3bar.The tank is connected by a valve to a friction
marissa [1.9K]

Answer:

Part a: <em>The total amount of energy transfer by the work done is 54.81 kJ.</em>

Part b: <em>The total amount of energy transfer by the heat is 54.81 kJ</em>

Explanation:

Mass of Carbon Dioxide is given as m1=3 kg

Pressure is given as P1=3 bar =300 kPA

Volume is given as V1=0.5 m^3

Pressure in tank 2 is given as P2=2 bar=200 kPa

T=290 K

Now the Molecular weight of CO_2 is given as

M=44 kg/kmol

the gas constant is given as

R=\frac{\bar{R}}{M}\\R=\frac{8.314}{44}\\R=0.189 kJ/kg.K

Volume of the tank is given as

V=\frac{mRT}{P_1}\\V=\frac{3 \times 0.189 \times 290}{300 }\\V=0.5481 m^3

Final mass is given as

m_2=\frac{P_2V}{RT}\\m_2=\frac{200\times 0.5481}{0.189\times 290}\\m_2=2 kg

Mass of the CO2 moved to the cylinder

m=m_1-m_3\\m=3-2=1 kg

The initial mass in the cylinder is given as

m_{(cyl)_1}=\frac{P_{(cyl)_1}V_1}{RT}\\m_{(cyl)_1}=\frac{200\times 0.5}{0.189 \times 290}\\m_{(cyl)_1}=1.82 kg

The mass after the process is

m_{(cyl)_2}=m_{(cyl)_1}+m\\m_{(cyl)_2}=1.82+1\\m_{(cyl)_2}=2.82\\

Now the volume 2 of the cylinder is given as

V_{(cyl)_2}=\frac{m_{(cyl)_2}RT}{P_2}\\m_{(cyl)_2}=\frac{2.82\times 0.189\times 290}{200}\\m_{(cyl)_1}=0.774 m^3

Part a:

So the Work done is given as

W=P(V_2-V_1)\\W=200(0.774-0.5)\\W=54.81 kJ

<em>The total amount of energy transfer by the work done is 54.81 kJ.</em>

Part b:

The total energy transfer by heat is given as

Q=\Delta U+W\\Q=0+W\\Q=54.81 kJ

As the temperature is constant thus change in internal energy is 0.

<em>The total amount of energy transfer by the heat is 54.81 kJ</em>

7 0
3 years ago
Only one of three balls A, B, and C carries a net charge q. The balls are made from conducting material and are identical. One o
Zarrin [17]

Answer:

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

Explanation:

The metals distribute the charge on all surface when they touch the surface increases so that charge density decreases and when the charge is separated into smaller in each metal.

Let's apply this principle to our case.

One of the spheres is loaded with a charge q, when touching a ball its charge is reduced to 1 / 2q for each ball.

         qA = ½ q

         qB = ½ q

         qC = 0

The total charge is q

we make a second contact

If we touch the ball A again with the other sphere not charged C, the chare is distributed and when separated it is reduced by half

         qA = 1/2 (q / 2) = ¼ q

         qC = ¼ q

         qB = ½ q

At this point all spheres have a charge,

      qA = ¼ q

      qb = ½ q

      qC = ¼ q

The total charge is q

Now let's contact spheres B and one of the other two

       Q = ½ q + ¼ q = ¾ q

When splitting the charge

        qB = ½ ¾ q = 3/8 q

        qC = ½ ¾ q = 3/8 q

        qA = ¼ q

The total charge is q

Note that the total load is always equal to q

Now let's analyze the given configuration

Let's look for the total load

       Q = qA + QB + QC

       Q = ½ q + 3/8 q + ¼ q

        Q = 9/8 q

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

8 0
3 years ago
A house is advertised as having 1560 square feet under roof. What is the area of this house in square meters?
strojnjashka [21]

Answer:

1 m = 3.28 ft

1 m^2 = 10.76 ft^2

1560 ft^2 / 10.76 ft^2 / m^2 = 145 m^2

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3 years ago
3. Work out the mass if an object is accelerated at <br> 10 m/s2 and has a weight of 98N.
elena-14-01-66 [18.8K]
Mass = Volume/Density. The answer is 9.8kg
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3 years ago
Which one describes how much matter an object contains, using SI units?
ahrayia [7]
Si units or Systeme' de Internationale' is a widely adopted unit system in measuring basic and derived dimensions In this case, the SI units here are kilograms, meter and seconds. Pounds is an English unit. mass is the measure of <span>how much matter an object contains, hence the answer is A. 43 kg.</span>
5 0
3 years ago
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