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ryzh [129]
3 years ago
5

Calculate the refractive index for a substance where the angle of incidence is 300 , the angle of refraction is 600 , and the re

fractive index of second substance is 1.5
Physics
1 answer:
Sophie [7]3 years ago
7 0

Answer:

η₁ = 2.6

Explanation:

Here, we will use snell's law to calculate the refractive of the substance:

\frac{\eta_2}{\eta_1} = \frac{Sin\theta_1}{Sin\theta_2}

where,

η₁ = refractive index of first substance = ?

η₂ = refractive index of second substance = 1.5

θ₁ = angle of incidence = 30°

θ₂ = angle of refraction = 60°

Therefore,

\frac{1.5}{\eta_1} = \frac{Sin\ 30^0}{Sin\ 60^0}

<u>η₁ = 2.6</u>

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We can see the image in most detail that having 400x magnification as compared to 100x.

<h3>What is magnification?</h3>

Magnification is the process in which the size of an object is enlarging but not physical size of something. Those instruments having high magnification power can shows us the image larger and due to which we can see that image clearly.

So we can conclude that we can see the image in most detail that having 400x magnification.

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The electric potential at a point in space is -890 V. If a 0.0285 C charge is placed there, what will its potential energy U be?
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A 220g mass is on a frictionless horizontal surface at the end of a spring that has a force constant of 7.0N/m The mass is displ
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Explanation:

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As potential energy and kinetic energy are constantly exchanging in SHM,

the position x where half of the original spring potential exists is found where

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An ideal monatomic gas initially has a temperature of 330 K and a pressure of 6.00 atm. It is to expand from volume 500 cm3 to v
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a. Final pressure= 5atm

b. Work done = 5000 Joules

<h3>How to determine the parameters</h3>

Given;

  • Temperature = 330K
  • P1 = 6 atm
  • V1 = 500cm^3
  • V2 = 1500cm^2

In adiabatic expansion, temperature is constant

P1V1 = P2V2

Now, let's substitute the values into the formula

6 × 500 = 1500 P2

300 = 1500P2

Make 'p2' subject of formula

P2 = 1500/300

P2 = 5 atm

The formula for work done is given as:

Workndone = P ∆ volume

Work done = 5 × ( 1500 - 500)

Work done = 5 × 1000

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