Answer:
I know the first one is C.) 4J. I don't know of the answer for the second oneis suppose to be in N/m form? but I got
2,500N/m
Answer:
197.5072.
Explanation:
According to the Coulomb's law, the magnitude of the electrostatic force of interaction between two charges 
and 
which are separated by the distance 
is given by
<em>where,</em> k is the Coulomb's constant.
For the case, when,
Then, using Coulomb's law,
For the case, when,
Then, using Coulomb's law, the new electric force between the charges is given by,
Frictional force = vertical force x coeff of friction = 590N x 0.045 = 26.55N
Mass of boy and sled = 590N / g = 590N / 9.8m/s^2 = 60.20 kg
Deceleration due to friction = 26.55N / 60.20kg = 0.44 m/s^2.
For constant acceleration we have:
v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and ti is time. In this case v = 0, u = 5.9 m/s, a = -0.44 m/s^2. So we have
0 = 5.9 - 0.44t
which gives t = 5.9 / 0.44 = 13.409 s.
Distance traveled in this time d = ut + 0.5at^2 = 5.9 x 13.409 - 0.5 x 0.44 x 13.409^2 = 39.56 m
<span>Answer: </span>40 meters
Answer:
Explanation:
F=ma
F in this case is the gravity acting on the 2kg object. Acceleration of gravity is 9.8 m/s^2. SF=ma, so
F = 2kg*(9.8 m/s^2) = 19.6 N
Now use this force to determine the mass of the object on the table:
F=ma
19.6 N (1N=kg*m/s^2) = m*(1.8 m/s^2)
m = 10.89 kg
