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zepelin [54]
2 years ago
10

Element X is a radioactive isotope such that every 25 years, its mass decreases by half. Given that the initial mass of a sample

of Element X is 50 grams, how much of the element would remain after 23 years, to the nearest whole number?
Mathematics
1 answer:
Julli [10]2 years ago
7 0
50*(.5)^(23/25)=26.43
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What is the force acting on a 16 kg object accelerating at 2.0 m/s2
alexira [117]

Answer:

32 n

Step-by-step explanation:

I had the same problem but I used a net force calculator the formula is F=MA so it would be 32=16/2.0 :)

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Plz help this question out
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2 years ago
Serika has hired Tom to build her a dollhouse. The dollhouse will be a scale model of her home, and the scale will be 2 inches :
sveticcg [70]

Answer:

96 square inches

Step-by-step explanation:

The scale is 2 inches : 3 feet

Thus for 18 feet in Serika's real house, the model is 18 * (2"/3') = 12 inches

For 12 feet in Serika's real house, the model is 12 * (2"/3') = 8 inches

Area of carpeting needed in Serika's dollhouse = 12" * 8" = 96 square inches

7 0
2 years ago
Lucy bought three books at a bookstore. Here are their prices (in dollars).
Valentin [98]

Answer:

41.82$

Step-by-step explanation:

The prices are

7.58$, 16$, 18.24$.

To get the total of all what Lucy bought, You add the prices altogether.

That is,

18.24$

+16.00$

+<u>0</u><u>7</u><u>.</u><u>5</u><u>8</u><u>$</u>

41.82$

The total amount of what Lucy bought is 41.82$

8 0
2 years ago
25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of
sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028

b) Probability that exactly 2 has only cats (p=0.15)

P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759

c) Probability that exactly 1 has cats and dogs (p=0.1)

P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508

8 0
3 years ago
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