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Roman55 [17]
4 years ago
9

The density of water at 40°C is 0.992 g/mL. What is the volume of 2.69 g of water at this temperature? V= mL​

Chemistry
1 answer:
vodka [1.7K]4 years ago
6 0

Answer:

\boxed {\tt 2.71169355 \ mL}

Explanation:

Density can be found using the following formula:

d=\frac {m}{v}

Rearrange the formula for v. Multiply both sides by v, then divide both sides by d.

d*v =\frac {m}{v}*v

d*v=m

\frac{d*v}{d}=\frac{m}{d}

v=\frac{m}{d}

The volume can be found by dividing the mass by the density. The mass is 2.69 grams and the density is 0.992 grams per milliliter.

m= 2.69 \ g\\d= 0.992 \ g/mL

Substitute the values into the formula.

v=\frac{2.69 \ g}{0.992 \ g/mL}

Divide. Note that the grams, or g, will cancel each other out.

v=\frac{2.69}{0.992 \ mL}

v= 2.71169355 \ mL

The volume of the water is 2.71169355 milliliters.

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The elements in the alkaline earth metals group; beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra), have two electrons in their outer electronic shell.

Explanation:

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4 0
3 years ago
Please I need help on these 3 questions. Thank You.​
Liula [17]

1.

V = 200 mL (volume)

c = 3 M = 3 mol/L (concentration)

First we convert mL to L:

200 mL = 0.2 L

Then we calculate the moles using the formula: n = V × c = 0.2 L × 3 mol = 0.6 mol

Finally, we just use the molar mass of CaF2 to calculate the actual mass:

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m = 0.6 mol × 78 g/mol = 46.8 g

2.

For this question the steps are exactly like the first question.

V = 50mL = 0.05 L

c = 12 M = 12 mol/L

n = V × c = 0.05 L × 12 mol/L = 0.6 mol

molar mass (HCl) = 36.5 g/mol

m = n × mm = 0.6 mol × 36.5 g/mol = 21.9 g.

3.

The steps for this question are the opposite way.

m(K2CO3) = 250 g

molar mass = 138 g/mol

n = m ÷ mm = 1.81 mol

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3 years ago
Of the well-characterized elements of group 7A, which would exhibit the following properties? It reacts with the alkali metals (
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Answer:

a. fluorine

Explanation:

Fluorine is the element of group 17 and period 2. The electronic configuration of the element is 1s^22s^22p^5.

Stable oxidation state = -1 of fluorine as it gains one electron to gain noble gas configuration.

With alkali metals, which have oxidation state of +1 form ionic compound of the form, MX where X is F.

Among the halogens, fluorine forms the most stable halide because of the comparable size of the hydrogen and fluorine. Thus, it is the weakest acid when compared with other hydrogen halides.

Fluorine is the most reactive in the halogen series and thus, combines with most of the elements.

Fluorine forms inter-halogen compounds of form XA only. Example - ClF.

Hence, option a is correct.

8 0
3 years ago
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