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3 years ago

C2H6(g) + O2(g) → CO2(g) + H2O(g)

Chemistry

2 answers:

Sindrei [870]3 years ago

6 0

2C2H6+7O2 - ->4CO2+6H20

attashe74 [19]3 years ago

5 0

Answer:

2C2H6 + 7O2 --> 4CO2 + 6H20

Explanation:

Balanced equation

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The coolant in automobiles is often a 50/50 % by volume mixture of ethylene glycol, C2H6O2, and water. At 20°C, the density of e

Misha Larkins [42]

Explanation:

Let the volume of the solution be 100 ml.

As the volume of glycol = 50 = volume of water

Hence, the number of moles of glycol = $\frac{mass}{molar mass}$

= $\frac{density \times volume}{molar mass}$

= $\frac{1.1088 \times 50}{62 g/mol}$

= 0.894 mol

Hence, number of moles of water = $\frac{50 \times 0.998}{18}$

= 2.77

As glycol is dissolved in water.

So, the molality = $0.894 \times \frac{1000}{49.92}$

= 17.9

Therefore, the expected freezing point = $-1.86 \times 17.9$

= $-33.31^{o}C$

Thus, we can conclude that the expected freezing point is $-33.31^{o}C$ .

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2 years ago

Mass of CuSO4● XH2O (g) = 1.6 grams BEFORE HEATING

Leokris [45]

0.06105 moles is the number of moles of water lost.

<h3>What is molar mass?</h3>

Molar mass is defined as the mass in grams of one mole of a substance.

Given data:

Mass of water = 1.1g

Molar mass water = 18.016 g/mol

Moles of water =?

These quantities are related by the following equation;

Moles = $\frac{Mass}{Molar \;mass}$

Substituting the values of the quantities and solving for moles, we have;

Moles = $\frac{1.1 }{18.016}$ = 0.06105 moles.

Hence, the 0.06105 moles is the number of moles of water lost.

Learn more about molar mass here:

brainly.com/question/12127540

#SPJ1

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2 years ago

Perform the following

Sever21 [200]

Answer:

8.97998

Explanation:

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3 years ago

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A blacksmith making a tool heats 525 grams of steel to 1230°C. After hammering the steel, she places it into a bucket of water t

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3 years ago

The surface of water can act like a sort of skin due to a property of liquids called

stiv31 [10]

Surface tension ..viscosity is the thickness of a liquid, doesn't fit here...condensation and evaporation are processes not properties.

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3 years ago

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