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givi [52]
3 years ago
8

C2H6(g) + O2(g) → CO2(g) + H2O(g)

Chemistry
2 answers:
Sindrei [870]3 years ago
6 0
2C2H6+7O2 - ->4CO2+6H20
attashe74 [19]3 years ago
5 0

Answer:

2C2H6 + 7O2 --> 4CO2 + 6H20

Explanation:

Balanced equation

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a truck start from attains a velocity of 20m/s after 10 second , calculate the acceleration. plz help with this ​
Marysya12 [62]

Answer:

= u +at

20m/s = 0 + a*10s

a = 20m//10s

a = 2m/s²

From the data given , it is not possible to calculate the displacement , because no direction of motion is given

But it is possible to calculate the distance travelled

Distance = ut + ½ *a*t²

distance = 0 + ½ * 2m/s * 10²s

distance = 100m

3 0
3 years ago
How many moles are in 13.0 grams of water​
ira [324]

13.0/18=.07222222

sig figs: 0.722 mole of water

6 0
4 years ago
Vanuation Question
Inessa05 [86]
Reckless driving I think
7 0
3 years ago
QUESTION 3 Consider a solution containing 0.80 M NaF and 0.80 M HF. Calculate the moles of HF and the concentration of HF after
Lisa [10]

Answer:

0.056moles HF and 0.70M

Explanation:

When a strong acid is added to a buffer, the acid reacts with the conjugate base.

In the system, NaF and HF, weak acid is HF and conjugate base is NaF. The reaction of NaF with HCl (Strong acid) is:

NaF + HCl → HF + NaCl

Initial moles of NaF and HF in 60.0mL of solution are:

NaF:

0.0600L × (0.80mol / L)= 0.048 moles NaF

HF:

0.0600L × (0.80mol / L)= 0.048 moles HF

Then, the added moles of HCl are:

0.0200L × (0.40mol / L) = 0.008 moles HCl.

Thus, after the reaction, moles of HF produced are 0.008 moles + the initial 0.048moles of HF, moles of HF are:

<em>0.056moles HF</em>

<em></em>

In 20.0mL + 60.0mL = 80.0mL = 0.0800L, molarity of HF is:

0.056mol HF / 0.0800L = <em>0.70M</em>

6 0
3 years ago
A process uses 63,400 SCF/h of natural gas. What is the annual cost of natural gas used in the process?
artcher [175]

Explanation:

It is known that 1 SCF produces approximately 1000 Btu of thermal energy.

As it is not mentioned for how many hours the gas is used in this process. Therefore, we assume that the total number of hours natural gas used in this process are as follows.

        365 \times 24 = 8760 hours

Now, we will calculate the annual cost of natural gas used in the process as follows.

               8760 \times 63400

              = 555384000 SCF

Hence, annual cost of natural gas used in this process = loss of thermal energy

This will be equal to,  555384000 \times 1000

                           = 555,384,000,000 BTU

Thus, we can conclude that the annual cost of natural gas used in the process is 555,384,000,000 BTU.

4 0
3 years ago
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