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3 years ago

C2H6(g) + O2(g) → CO2(g) + H2O(g)

Chemistry

2 answers:

Sindrei [870]3 years ago

6 0

2C2H6+7O2 - ->4CO2+6H20

attashe74 [19]3 years ago

5 0

Answer:

2C2H6 + 7O2 --> 4CO2 + 6H20

Explanation:

Balanced equation

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Formula for salt I will mark u brain list

Vesnalui [34]

Answer:

The formula for salt is NaCl or Sodium chloride

5 0

3 years ago

Which graph shows the relationship between the temperature and volume of agas according to Charles's law?Volume vs. Temperature

solmaris [256]

Graph D.

Charles's law states that at the same pressure, the Volumen of a gas is proportional to its temperature (absolute temperature).

This is

V = K T, where K is the constant of proportionallity.

You can also write it in the form

V1 / V2 = T1/ Ts

When Temperature rise Volumen rise in a proportional way. If Temperature doubles Volumen doubles, if Tempearature is decreases to on third, Volume will decrease to one third.

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3 years ago

A system fitted with a piston expands when it absorbs 53.1 ) of heat from the surroundings. The piston is working against a pres

Hoochie [10]

Answer:

d. 60.8 L

Explanation:

Step 1: Given data

Heat absorbed (Q): 53.1 J

External pressure (P): 0.677 atm

Final volume (V2): 63.2 L

Change in the internal energy (ΔU): -108.3 J

Step 2: Calculate the work (W) done by the system

We will use the following expression.

ΔU = Q + W

W = ΔU - Q

W = -108.3 J - 53.1 J = -161.4 J

Step 3: Convert W to atm.L

We will use the conversion factor 1 atm.L = 101.325 J.

-161.4 J × 1 atm.L/101.325 J = -1.593 atm.L

Step 4: Calculate the initial volume

First, we will use the following expression.

W = - P × ΔV

ΔV = - W / P

ΔV = - 1.593 atm.L / 0.677 atm = 2.35 L

The initial volume is:

V2 = V1 + ΔV

V1 = V2 - ΔV

V1 = 63.2 L - 2.35 L = 60.8 L

7 0

2 years ago

Explain why the Amazon River does not create deltas?

jeka57 [31]

Answer:

The ocean currents are too strong by the Amazon River to form deltas.

Explanation:

The Atlantic has sufficient wave and tidal energy to carry most of the Amazon's sediments out to sea, thus the Amazon does not form a true delta. The great deltas of the world are all in relatively protected bodies of water, while the Amazon empties directly into the turbulent Atlantic.

4 0

2 years ago

Determine the limiting reactant (lr) and the mass (in g) of nitrogen that can be formed from 50.0 g n2o4 and 45.0 g n2h4. some p

Licemer1 [7]

N2O4(l) + 2 N2H4(l) → 3 N2(g) + 4 H2O(g)
1) to calculate the limiting reactant you need to pass grams to moles.
 moles is calculated by dividing mass by molar mass

mass of N2O4: 50.0 g
molar mass of N2O4 = 92.02 g/mol
molar mass of N2H4 = 32.05 g/mol.
mass of N2H4:45.0 g

moles N2O4=50.0/92.02 g/mol= 0,54 mol of N2O4
moles N2H4= 45/32.05 g/mol= 1,40 mol of N2H4

 2)
By looking at the balanced equation, you can see that 1 mol of N2O4 needs 2 moles of N2H4 to fully react . So to react 0,54 moles of N2O4, you need 2x0,54 moles of N2H4 moles
N2H4 needed = 1,08 moles.
You have more that 1,08 moles N2H4, so this means the limiting reagent is not N2H4, it's N2O4. The molecule that has molecules that are left is never the limiting reactant.

3) 1 mol of N2O4 reacting, will produce 3 mol of N2 (look at the equation)
There are 0,54 mol of N2O4 available to react, so how many moles will produce of N2?
1 mol N2O4------------3 mol of N2
0,54 mol N2O4--------x
x=1,62 mol of N2

4) the only thing left to do is convert the moles obtained, to grams.
We use the same formula as before, moles equal to mass divided by molar mass.
$moles= \frac{grams}{molar mass}$ (molar mass of N2= 28)
1,62 mol of N2= mass/ 28
mass of N2= 45,36 grams

4 0

3 years ago