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2 years ago

Can someone please help me with this I need help asap

Chemistry

1 answer:

DiKsa [7]2 years ago

6 0

Answer:

???

Explanation:

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How many grams of CaCl2 are needed to make 277.8g of a solution that is 31.5% (m/m) in water? Note that mass is not technically

Sveta_85 [38]

<u>Answer:</u> The mass of calcium chloride present in given amount of solution is 87.5 g

<u>Explanation:</u>

We are given:

Mass of solution = 277.8 grams

Also, 31.5 % (m/m) of calcium chloride in water. This means that 31.5 g of calcium chloride is present in 100 g of solution.

To calculate the mass of calcium chloride in the given amount of solution, we use unitary method:

in 100 g of solution, the mass of calcium chloride present is 31.5 g

So, 277.8 g of solution, the mass of calcium chloride present is $\frac{31.5}{100}\times 277.8=87.5g$

Hence, the mass of calcium chloride present in given amount of solution is 87.5 g

8 0

3 years ago

92 grams of ethanol,C2H5OH, is dissolved in 1 liter of solution. Determine the molarity (M)

const2013 [10]

Answer: 1.997 M

Explanation:

molarity = moles of solute/liters of solution or $M = \frac{mol}{L}$

first we have to find our moles of solute (mol), which you can find by dividing the mass of solute by molar mass of solute

mass of solute: 92 g

molar mass of solute: 46.08 g/mol

let's plug it in:

$\frac{92 g}{46.08 g/mol} = 1.997 mol$

next, we plug it into our original equation:

$\frac{1.997mol}{1 L} = 1.997 M$

4 0

3 years ago

Someone please help fast!!!please

Crank

Answer:

7276783

Explanation:

8765467

4 0

2 years ago

How do I calculate the molecular and molar masses of compounds

ludmilkaskok [199]

Answer:

The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance (mol). The molar mass of a compound can be calculated by adding the standard atomic masses (in g/mol) of the constituent atoms.

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3 years ago

What do AM radio, FM radio, television, and cell phones have in common?

Katen [24]

C is the correct answer

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3 years ago