For this case we have that the area of the kite is formed by the ara of two triangles with the same base of
meters and one with height 9 meters and another with height 6 meters.
So:
![A = \frac {1} {2} b * h + \frac {1} {2} b * h\\A = \frac {1} {2} 18 * 9 + \frac {1} {2} 18 * 6\\A = \frac {1} {2} 162+ \frac {1} {2} 108\\A = 81 + 54\\A = 135 \ m ^ 2](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%20%7B1%7D%20%7B2%7D%20b%20%2A%20h%20%2B%20%5Cfrac%20%7B1%7D%20%7B2%7D%20b%20%2A%20h%5C%5CA%20%3D%20%5Cfrac%20%7B1%7D%20%7B2%7D%2018%20%2A%209%20%2B%20%5Cfrac%20%7B1%7D%20%7B2%7D%2018%20%2A%206%5C%5CA%20%3D%20%5Cfrac%20%7B1%7D%20%7B2%7D%20162%2B%20%5Cfrac%20%7B1%7D%20%7B2%7D%20108%5C%5CA%20%3D%2081%20%2B%2054%5C%5CA%20%3D%20135%20%5C%20m%20%5E%202)
ANswer:
Option B
Answer:
See below ~
Step-by-step explanation:
(a) To find y-intercept :
- y = -x² + 2x + 15
- y = -(0)² + 2(0) + 15
- y = 15
- M is : (0, 15)
(b) Finding x-intercepts :
- 0 = -x² + 2x + 15
- -x² + 5x - 3x + 15 = 0
- x(-x + 5) + 3(-x + 5) = 0
- (x + 3)(-x + 5) = 0
- x + 3 = 0 ⇒ x = -3
- -x + 5 = 0 ⇒ x = 5
- P and Q are : (-3, 0) and (5, 0)
(C) Finding vertex :
- Vertex is (h, k)
- h = -b/2a = -2/2(-1) = 1
- k = -(1)² + 2(1) + 15
- k = -1 + 2 + 15
- k = 16
- The maximum point is : (1, 16)
Answer:
Exactly 1 solution
Step-by-step explanation:
When you graph it, you'll see that both lines intersect at 1 point in time only
Answer: 54
Explanation:
1 yard = 3 feet. 3 yards = 3 x 3 = 9 feet.
Area of the floor = 9 x 9 = 81 square feet
Total tiles required = <span>81÷1 1/2</span>
<span><span><span>81×<span>2/3</span>=<span>54</span></span></span></span>