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2 years ago

6

Press on the picture

2 answers:

scoray [572]2 years ago

7 0

B is the correct answer

Aleksandr-060686 [28]2 years ago

6 0

Answer:

bet, I pressed the picture (lol)

Step-by-step explanation:

it's B

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At a restaurant you only have 20 dollars to spend on dinner. in addition to the cost of the meal you must pay only 5% sales tax

aev [14]

Alright so to do this you need some basic algebra
you have to pay an extra 20% of whatever you buy
thus we can make the following equation
.2x+x=20 (since 20 is the amount of money you have)
combining the like terms,
1.2x=20
and finally, dividing both sides by 1.2
x=$16.67
don't forget to check!
.05*16.67=.83 (sales tax makes the total $17.5)
.15*16.67=2.5 (tip makes the total $20)
whaddya you know, it works!
most expensive item you can buy will cost $16.67
hope this helped!

4 0

2 years ago

Helppp I will make you a brainlist!! <br><br> A=[4 6 5 ] , then what is 2A? <br> 6 10 7

KATRIN_1 [288]

Answer:

So we have a matrix
We have to do 2 × A
So 2[ 4 6 5 ]
Multiply in
So 2 × A = [8 12 10]

5 0

2 years ago

Which set of ordered pairs belongs to a linear function?

masya89 [10]

Answer:

<u><em>Hi there the correct answer will be is B) (-1,5), (1, 3), (3, 1), (5,0)</em></u>

hope it helps to your question!

7 0

3 years ago

5/12 + 2/3 <br> Please help

AnnZ [28]

Answer:

The answer is 1 and 1/12 you can’t simplify the problem but this is the answer

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago