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Rama09 [41]
4 years ago
11

Give an example, other than making ice-cream or a slushy, where the effect of salt on the phase change of water is useful in eve

ryday life.
ASAP PLS AND THANK YOU
Chemistry
2 answers:
guapka [62]4 years ago
7 0

Answer:

Putting salt on the ground to melt ice or snow I mean.

Explanation:

horrorfan [7]4 years ago
7 0
Using salt to melt sleet and snow not black ice tho u cant melt that
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What is the mass of 0.0150 moles of Na₂SO4 (molar mass = 142.04 g/mol)?
olga2289 [7]

Answer:

2.13 g

Explanation:

(142.04)(0.0150) = 2.13 g

4 0
2 years ago
What do acids and bases have in common apex?
disa [49]

Both acids and bases produce a part of a water molecule. Bases dissociate hydroxide (–OH) ions and acids, hydrogen (H+) ions that when combined form water. Both are also very corrosive when they are strong enough that they fully dissociate in water.

8 0
3 years ago
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Phosphorus reacts with oxygen to form diphosphorus pentoxide, P2O5 . 4P(s)+5O2(g)⟶2P2O5(s) How many grams of P2O5 are formed whe
iogann1982 [59]

Answer:

The answer to your question is:

Explanation:

2.45 g of Phosphorus

MW P = 31 g

MW P2O5 = 2(31) + 5(16) = 142 g

From the balance reaction

               4 P      ⇒ 2 P2O5

Then     4(31) g P    ⇒  2 (142)  g P2O5

       124g  of P       ⇒  284 g   of P2O5              Rule of three

            2.45g P      ⇒      x

x = 2.45 x 284/124 = 695.8/124 = 5.61 g of P2O5

3 0
3 years ago
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How does understanding chemistry help us in the real world
choli [55]
It helps us make informed decisions
7 0
4 years ago
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A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr
sertanlavr [38]

Answer: The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.947 atm

P_2 = final pressure of gas = 0.987 atm

V_1 = initial volume of gas = 150 ml

V_2 = final volume of gas = 144 ml    

T_1 = initial temperature of gas = 25^0C=(25+273.15)K=298.15K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}

T_2=298.31K=(298.31-273.15)^0C=25.16^0C

The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

4 0
3 years ago
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