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levacccp [35]
4 years ago
5

What is 7 and 5/6 as an improper fraction

Mathematics
2 answers:
swat324 years ago
7 0
47/6 is the answer hope this helps
Margaret [11]4 years ago
4 0
47/6. Hope this helps!
You might be interested in
Semielliptical Arch Bridge An arch for a bridge over a highway is in the form of half an ellipse. The top of the arch is 20 feet
photoshop1234 [79]

Answer:

the span of the bridge is 73.7 feet

Step-by-step explanation:

The equation of an ellipse with a vertical major axis(i.e major axis parallel to y axis) is given by:

\frac{(x-h)^{2} }{b^{2} } + \frac{(y-k)^{2} }{a^{2} }= 1 a>b

where (h,k) are the coordinates of the center of the ellipse, a is the length of the major axis and b is the length of the minor axis

For this problem, the center of the ellipse (h,k) = (0,0)

Therefore:

\frac{(x)^{2} }{b^{2} } + \frac{(y)^{2} }{a^{2} }= 1

The top of the arch is 20 feet above the ground level (the major axis), therefore a=20

length of the major axis = 2a= 2*20 = 40

\frac{x^{2} }{b^{2} } + \frac{y^{2} }{20^{2} }= 1\\\frac{x^{2} }{b^{2} } + \frac{y^{2} }{400 }= 1

The coordinates of the ellipse (x,y) = (28,13)

\frac{28^{2} }{b^{2} } + \frac{13^{2} }{400 }= 1

\frac{28^{2} }{b^{2} } + 0.4225= 1

\frac{784 }{b^{2} } = 0.5775

b² ≅ 1358

b≅36.85

Length of minor axis (2b) = 73.7 feet.

the span of the bridge is 73.7 feet

7 0
4 years ago
PLEASE HELP QUICK!!!!!!!!!!!!!!
telo118 [61]

Answer:

180a-100b= 100c *  50

Step-by-step explanation:

was apart of my unit test goodluck!

8 0
3 years ago
Brianna has a sheet of paper that is 6 feet long.she cuts the length of paper into sixth and then cuts the length of each of the
Inga [223]
72 inches i think im not sure 

7 0
3 years ago
Order from least to greatest 0, 8/3, -2/5, 1 and 3/4, 19/10, -3/4
katrin [286]

Answer:-2/5, -3/4, 0, 3/4, 19/10, 8/3

Step-by-step explanation:

3 0
4 years ago
Can someone help answer this question Ive tried a lot and couldnt do it.
aleksklad [387]

Answer:

1222

Step-by-step explanation:

You have a triangular prism on top of a rectangular prism.  The surface area is the sum of the areas of the exposed faces.

Starting with the triangular prism, the surface area is the area of the two triangular bases plus the area of the two rectangular sides (the bottom rectangular face is ignored).

A = ½ (10) (12) + ½ (10) (12) + (13) (9) + (13) (9)

A = 60 + 60 + 117 + 117

A = 354

The surface area of the rectangular prism is the area of the two rectangular bases (front and back), plus the two walls (left and right), plus the bottom, plus the top (minus the intersection with the top prism).

A = (19) (11) + (19) (11) + (9) (11) + (9) (11) + (19) (9) + (19) (9) − (10) (9)

A = 209 + 209 + 99 + 99 + 171 + 171 − 90

A = 868

So the total surface area is:

354 + 868

1222

5 0
3 years ago
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