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just olya [345]
2 years ago
7

Is the graph of the function increasing, decreasing, or constant?

Mathematics
2 answers:
Gemiola [76]2 years ago
5 0

Answer:

Increasing

Step-by-step explanation:

If the right end of the line is higher, the function is increasing. If the right end is lower, it’s decreasing. If it’s flat, it is constant.

Goshia [24]2 years ago
3 0

Answer:

increasing. This graph has a positive slop and to know weather a  line has a positive or negative slope follow this:

a line that looks like so / has a positive slope while a line like this \ has a negative slope. a line like _ has a slope of 0 and a line like so:   l     has an undefined slope

Step-by-step explanation:

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Which of the following is true about how information is processed by the interviewer? a. Negative information is given a relativ
son4ous [18]

Answer:

A. Negative information is given a relatively larger weight than positive information.

Step-by-step explanation:

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During the recruitment and/or interview processes, the recruiter is presented with a pool of candidates with varying skills and competencies. The scenario here will be that the recruiter will come up with penciled skills and character to;

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3 0
3 years ago
Plz help me with my algebra
Rus_ich [418]
The answer is a(x)=x+3
3 0
3 years ago
Read 2 more answers
Differential cos^2x dy/dx =e^y-tanx​
gulaghasi [49]

Answer:

y=t−1+ce

−t

where t=tanx.

Given, cos

2

x

dx

dy

+y=tanx

⇒

dx

dy

+ysec

2

x=tanxsec

2

x ....(1)

Here P=sec

2

x⇒∫PdP=∫sec

2

xdx=tanx

∴I.F.=e

tanx

Multiplying (1) by I.F. we get

e

tanx

dx

dy

+e

tanx

ysec

2

x=e

tanx

tanxsec

2

x

Integrating both sides, we get

ye

tanx

=∫e

tanx

.tanxsec

2

xdx

Put tanx=t⇒sec

2

xdx=dt

∴ye

t

=∫te

t

dt=e

t

(t−1)+c

⇒y=t−1+ce

−t

where t=tanx

8 0
2 years ago
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