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Maurinko [17]
3 years ago
6

Help? The question is down below

Chemistry
1 answer:
Bad White [126]3 years ago
4 0

Answer:

They need to have a full outer shell to be stable so they bond with each other and share electrons to become stable forming a compound.

Explanation:

Hope this helps!

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H-h+cl+cl____2h-cl... calculate the energy needed to break the bond​
Elenna [48]
The energy required to break one mole of Cl - Cl bond is 242 kJ/mol
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4 years ago
Who was the first hispanic justice of the United States Supreme Court
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Justice Sonia Sotomayor<span> is the first Latina to sit on the United States Supreme Court.</span>
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4 years ago
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Ammonium chloride, ammonium sulfate and ammonium nitrate are used in fertilisers.
Hoochie [10]

Answer:

1.0625 g

Explanation:

Number of moles in 5g of NH4NO3 = 5.0g/80g/mol = 0.0625 moles

Again the balanced reaction equation is;

NH3 + HNO3 → NH4NO3

So,

1 mole of NH3 yields 1 mole of NH4NO3

x moles of NH3 yields 0.0625 moles of NH4NO3

x = 0.0625 moles of NH3

Mass of NH3 = number of moles * molar mass

Mass of NH3 = 0.0625 moles * 17g/mol

Mass of NH3 = 1.0625 g

7 0
3 years ago
p32p32 is a radioactive isotope with a half-life of 14.3 days. if you currently have 63.163.1 g of p32p32 , how much p32p32 was
AlekseyPX

Answer:

92.93 g

Explanation:

Number of half lives that have elapsed in eight days =8/14.3 = 0.559

Fraction of the radioactive nuclide that remains after 0.559 half lives is given by

N/No=(1/2)^0.559

Where N= mass of radioactive nuclides remaining after a time t

No= mass of radioactive nuclides originally present

N/No=(1/2)^0.559= 0.679

Mass of nuclides present eight days before= 63.1g/0.679

Mass of nuclides present eight days before=92.93 g

6 0
4 years ago
What is the mass of 1.71 ✕ 1023 molecules of h2so4?
Anuta_ua [19.1K]
The equation for calculating a mass is as follows:

m=n×M

Molar mass (M) we can determine from Ar that can read in a periodical table, and a number of moles we can calculate from the available date for N:

n(H2SO4)=N/NA

n(H2SO4)= 1.7×10²³ / 6 × 10²³

n(H2SO4)= 0.3 mole

Now we can calculate a mass of H2SO4:

m(H2SO4) = n×M = 0.3 × 98 = 27.8 g



7 0
4 years ago
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