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Arlecino [84]
4 years ago
7

What is the mass of 1.71 ✕ 1023 molecules of h2so4?

Chemistry
1 answer:
Anuta_ua [19.1K]4 years ago
7 0
The equation for calculating a mass is as follows:

m=n×M

Molar mass (M) we can determine from Ar that can read in a periodical table, and a number of moles we can calculate from the available date for N:

n(H2SO4)=N/NA

n(H2SO4)= 1.7×10²³ / 6 × 10²³

n(H2SO4)= 0.3 mole

Now we can calculate a mass of H2SO4:

m(H2SO4) = n×M = 0.3 × 98 = 27.8 g



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Answer:

Oxidizing element: Mg

Explanation:

Reaction of magnesium and oxygen can be written as:

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while writting chemical reaction between two atom or element then write their natural form i.e. how that atom or element exist in the nature.

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This equation is showing that speed is inversely related to the square root of its molar mass. As carbon dioxide has a bigger MW than carbon monoxide, the speed of effusion of carbon dioxide is lower doing its ballon biggest than carbon monoxide ballon, thus: <em>The smallest ballon is the ballon X</em>

<em></em>

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<h3>Answer:</h3>

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<h3>Explanation:</h3>
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