1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
PilotLPTM [1.2K]
3 years ago
11

Earths energy sources include renewable and non renewableresources. name at least three sources of energy that could be used in

your house. then describe the ideal energy source for generatinng most of you homes electricity, and explain why you chose thst source.
Physics
1 answer:
enot [183]3 years ago
6 0

Electricity.

Solar Energy

Wind Energy


In a home, the best option as a source of energy is electricity. Though some choose to use solar energy to power their devices, electricity is more cost effective.

You might be interested in
The drag force that resists the motion of a car traveling at 80 km h^- 1 is 300 N.
kobusy [5.1K]

The power require to keep the car traveling is 6,666 W.

The power of the engine at the given efficiency is 3,999.6 W.

<h3>What is Instantaneous power?</h3>

This the product of force and velocity of the given object.

The power require to keep the car traveling is calculated as follows;

P = Fv

P = 300\ N \ \times  \ \frac{80 \ kmh^{-1}}{3.6 \ km h^{-1}/m/s} \\\\&#10;P = 300 \ N \times 22.22 \ m/s\\\\&#10;P = 6,666 \ W

The power of the engine at the given efficiency is calculated as follows;

E = \frac{P_{out}}{P _{in}} \times 100\%\\\\&#10;60\% = \frac{P_{out}}{6,666} \times 100\%\\\\&#10;0.6 = \frac{P_{out}}{6,666} \\\\&#10;P_{out} = 3,999.6 \ W

Learn more about efficiency here: brainly.com/question/15418098

8 0
2 years ago
His the bottom, or lowest point, of a wave.
Gnom [1K]

A trough is the lowest point in a wave.

5 0
3 years ago
Read 2 more answers
A father is pulling his child on a sled in the snow. According to Newton’s Third Law, the force the father exerts on the sled is
viktelen [127]
That is because there are other forces like the friction forces that apply differently on both of them. The frictional forces applied to the sled are smaller than they are on the father, for example, so it's possible for him to pull it.
5 0
4 years ago
a Car with a mass of 2000 kg is moving around a circular curve at a uniform velocity of 25 m/s the curve has a radius of 80 m wh
Viefleur [7K]
Well, first of all, the car is not moving at a uniform velocity, because,
on a curved path, its direction is constantly changing.  Its speed may
be constant, but its velocity isn't.

The centripetal force on a mass 'm' that keeps it on a circle with radius 'r' is

             F = (mass) · (speed)² / (radius).

For this particular car, the force is

                    (2,000 kg) · (25 m/s)² / (80 m)

                 = (2,000 kg) · (625 m²/s²) / (80 m)

                 = (2,000 · 625 / 80)  (kg · m / s²)

                 =              15,625  newtons .
5 0
4 years ago
A 41 kg girl and a 5.0 kg sled are on the frictionless ice of a frozen lake, 15 m apart but connected by a rope of negligible ma
goldfiish [28.3K]

(a) 0.8 m/s^2

The force exerted on the sled is F = 4.0 N. We can calculate the acceleration of the sled by using Newton's second law:

F=ma

where

m = 5.0 kg is the mass of the sled

a is the acceleration of the sled

Solving the equation for a, we find:

a=\frac{F}{m}=\frac{4.0 N}{5.0 kg}=0.8 m/s^2

(b) 0.098 m/s^2

According to Newton's third law (action-reaction law), since the girl exerts a force on the sled, then the sled exerts an equal and opposite force on the girl as well. This means that the force exerted on the girl is also F = 4.0 N. As before, we can calculate the acceleration of the girl by using Newton's second law:

F=ma

where

m = 41 kg is the mass of the girl

a is the acceleration of the girl

Solving the equation for a, we find:

a=\frac{F}{m}=\frac{4.0 N}{41 kg}=0.098 m/s^2

(c) 5.8 s

Taking the initial position of the girl as x = 0, the position at time t of the girl is given by:

x(t)=\frac{1}{2}a_g t^2

where a_g = 0.098 m/s^2 is the acceleration of the girl.

The sled starts instead its motion from x = 15 m, so its position at time t is given by

x'(t)=15-\frac{1}{2}a_s t^2

where a_s=0.8 m/s^2 is the acceleration of the sled, and the negative sign is due to the fact that the sled accelerates in opposite direction to the girl's acceleration.

The girl and the sled meet when x(t) = x'(t). So, we find:

\frac{1}{2}a_g t^2=15-\frac{1}{2}a_s t^2\\(a_g+a_s) t^2=30 m\\t=\sqrt{\frac{30 m}{a_g+a_s}}=\sqrt{\frac{30 m}{0.8 m/s^2+0.098 m/s^2}}=5.8 s

4 0
4 years ago
Other questions:
  • Which object is least likely to allow light to pass through it?
    13·2 answers
  • Atoms are happy (they will not readily react with other elements) when they have a full outside ring of
    15·1 answer
  • A thin spherical shell of radius 7.6 cm carries a uniform surface charge density of 6.7 times 10-9 C/m2. The magnitude of the el
    9·1 answer
  • What is the unit for electric charge?<br> Kilogram<br> Newton<br> Electron<br> Coulomb
    8·2 answers
  • You can see lightning before you can hear the thunder. Which is the best explanation for this?
    11·2 answers
  • How might you describe the mathematical procedure of finding the displacement when an object travels in two opposite directions?
    14·1 answer
  • In which of the following situations are there a force on the object balanced
    15·1 answer
  • Question:Which kind of nuclear decay is shown below? Please answer!!!
    12·1 answer
  • 2. Your latitude indicates how far you are from the equator, a
    14·1 answer
  • An object moving with a speed of 5m/s comes to rest in 10s after the brakes are applied . What is the initial velocity​?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!