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3 years ago

Which electric component provides energy to the circuit of a flashlight?

2 answers:

6 0

"Battery" <span> provides energy to the circuit of a flashlight

In short, Your Answer would be Option A

Hope this helps!</span>

riadik2000 [5.3K]3 years ago

6 0

<span>The flow of the electricity is activated when you push the switch into the "on" position, giving you light. The flow of electricity is broken when the switch is pushed into the "off" position, thus turning off the light.</span>

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Apples are stored in a container (width = length = 3.5 ft) that is filled to a depth of 2.75 feet. If the unit density of an app

Agata [3.3K]

Answer:

The mass of the apples in the box are 1145.95 lb.

Explanation:

Given that,

Width = 3.5 ft

length = 3.5 ft

Depth = 2.75 feet

Density = 49.3 lb/ft³

We need to calculate the volume

Using formula of volume

$V=l\times h\times b$

Put the value

$V=3.5\times3.5\times2.75$

$V=33.6875\ ft^3$

We need to calculate the mass

Using formula of density

$\rho=\dfraxc{m}{V}$

$m=\rho\timesV$

Put the value into the formula

$m=49.3\times33.6875$

$m=1660.79\ lb$

But porosity is 31 % so apples is 69% mass of total container.

So, Total mass in pounds is

$M=\dfrac{69}{100}\times1660.79$

$M=1145.95\ lb$

Hence, The mass of the apples in the box are 1145.95 lb.

8 0

2 years ago

Force usually has the symbol F. It is a vector. What is the correct way to write the symbol to show that it is a vector?

const2013 [10]

Answer:

(B) F with a line on top

Explanation:

There is no one single 'correct' way to denote a vector. Most typical is a line over the symbol: $\overline{F}$ , or an arrow over the symbol: $\vec F$ . (However, if you want to use your own vector notation, for example, by printing the symbol in bold, then that is fine, too, as long as you clearly define this upfront),

4 0

3 years ago

In an experiment to estimate the acceleration due to gravity, a student drops a ball at a distance of 1 m above the floor. His l

anyanavicka [17]

Answer:

$9.45179\ m/s^2$

$s=4.725895t^2$

Explanation:

t = Time taken = 0.46

u = Initial velocity

v = Final velocity

s = Displacement = 1 m

a = Acceleration

$s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0\times 0.46+\frac{1}{2}\times a\times 0.46^2\\\Rightarrow a=\frac{1\times 2}{0.46^2}\\\Rightarrow a=9.45179\ m/s^2$