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3 years ago

What is cutoff wavelength?

Physics

1 answer:

LenKa [72]3 years ago

3 0

Answer:

The cutoff wavelength is the minimum wavelength in which a particular fiber still acts as a single mode fiber. Above the cutoff wavelength, the fiber will only allow the LP01 mode to propagate through the fiber (fiber is a single mode fiber at this wavelength).

Explanation:

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Linus builds an electrical circuit with a battery and with wires that carry the current. As the battery weakens, the current als

pantera1 [17]

Answer:

The field gets weaker

Explanation:

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3 years ago

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Which of the following is an example of a technological solution to water pollution in a local pond?

dexar [7]

Sure: ths is called protyping and lets yu get a sende fo the effeciveness tof the cahnge and the cost of the change.

A - just like the scientific principle syu what to know what other know or have learned. Example would it be silly to build a nuclear power de-salinatiztion plant when a dam in the mountains wuld dothe savme thng and perhaps have the advatage of using local labor and preveinting floods and givng of hydro eletic power. 

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3 years ago

Caregivers who are observed to be abusive or neglectful have been associated with the __________ type of attachment. A. secure B

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3 years ago

Mr. F has taken in a lot of fluid and put out very little. During this period his heart rate has increased a little and his bloo

mezya [45]

Answer:

Explanation:

What can be infer from Mr. F situation is that his body is raising blood pressure by both increasing blood volume with all this fluid intake and increasing heart rate. Something may be wrong with his blood volume.

4 0

3 years ago

Imagine you are holding a box in your hand, the force required for you to hold the box with mass 4.54kg and you want to accelera

svetlana [45]

Answer:

(a) Fₓ = 0 N

$F_y$ = 9.08 N

(b)

(a) Fₓ = 0 N

$F_y$ = 9.08 N

Fₓ = 9.08 N

Explanation:

The magnitude of the force will remain the same in each case, which is given as follows:

F = ma (Newton's Second Law)

where,

F = force = ?

m = mass = 4.54 kg

a = acceleration = 2 m/s²

Therefore,

F = (4.54 kg)(2 m/s²)

F = 9.08 N

Now, we come to each scenario:

(a)

Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:

Fₓ = 0 N

For upward direction the force will be positive:

$F_y$ = 9.08 N

(b)

Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:

Fₓ = 0 N

For upward direction the force will be negative:

$F_y$ = - 9.08 N

(c)

Since the motion is in the horizontal direction. Therefore the magnitude of the force in y-direction will be zero:

$F_y$ = 0 N

Fₓ = 9.08 N

3 0

3 years ago