Calculate the work done on a Pressure / Volume (PV) isothermal expansion where 400 Pa and 0.08 volume in m3?

If there is gravity where the International Space Station (ISS) is located above Earth, why doesn’t the space station get pulled

nasty-shy [4]

Answer:

Yes. Gravity is 90% of what it is on the earth's surface. ISS moves at such high speeds that the curve of its fall will always match the curve of the earth and so will never hit the earth.

Explanation:

The location of the International Space Station (ISS) is at an altitude of about 200 or 250 miles above the earth's surface. Since gravity decreases with altitude, it is less at that height. Gravity is still present there. Since the ISS is in orbit around the earth, the condition is of free fall. Result of this free fall is apparent weightlessness. The high speed of the ISS allows it to orbit around in such a way that the gravitational pull of the earth is equal to the centripetal force experienced by the ISS in its orbit.

The conditions which make it remain in space are similar to how the moon stays in the orbit around the earth. Moon is also in free fall but it never falls down to earth.

7 0

3 years ago

A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a sp

dusya [7]

from the question you can see that some detail is missing, using search engines i was able to get a similar question on "https://www.slader.com/discussion/question/a-student-throws-a-water-balloon-vertically-downward-from-the-top-of-a-building-the-balloon-leaves-t/"

here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?

Answer:

(A) 26 m/s

(B) 32.4 m

(C) v = 15.4 m/s

Explanation:

initial speed (u) = 6.4 m/s

acceleration due to gravity (a) = 9.9 m/s^[2}

time (t) = 2 s

(A) What is its speed after falling for 2.00s?

from the equation of motion v = u + at we can get the speed

v = 6.4 + (9.8 x 2) = 26 m/s

(B) How far does it fall in 2.00s?

from the equation of motion $s=ut+0.5at^{2}$ we can get the distance covered

s = (6.4 x 2) + (0.5 x 9.8 x 2 x 2)

s = 12.8 + 19.6 = 32.4 m

c) What is the magnitude of its velocity after falling 10.0m?

from the equation of motion below we can get the velocity

$v^{2} = u^{2} + 2as\\v^{2} = 6.4^{2} + (2x9.8x10)\\V^{2} = 236.96\\v = \sqrt{236.96}$

v = 15.4 m/s

7 0

3 years ago

A major contemporary learning view of personality which holds that personality traits result from a

DIA [1.3K]

Answer:

21

Explanation:

21 is x because 211211 1 1 1 1 1aghh

3 0

3 years ago

Read 2 more answers

The displacement of a car is a function of time as follows: x(t)=25+3.0t², with x is in meters. Find the average velocity betwee

aniked [119]

Answer: 15m/s

Explanation: <u>Average</u> <u>Velocity</u> is vector describing the total displacement of an object and the time taken to change its position. It is represented as:

$v=\frac{\Delta x}{\Delta t}$