<span>The formula for inductance X is X=2*pi*freq*L. With the given information, we solve for L. The equation becomes: L = X/(2*pi*freq). Substituting the known variables gives us L = 147ohms / (2*pi*2000hz). Solving for L, L equals .0117. The inductance of this inductor is 11.7 mH.</span>
Answer:
The actual angle is 30°
Explanation:
<h2>Equation of projectile:</h2><h2>y axis:</h2>
the velocity is Zero when the projectile reach in the maximum altitude:
When the time is vo/g the projectile are in the middle of the range.
<h2>x axis:</h2>
R=Range
**sin(2A)=2sin(A)cos(A)
<h2>The maximum range occurs when A=45°
(because sin(90°)=1)</h2><h2>The actual range R'=(2/√3)R:</h2>
Let B the actual angle of projectile
2B=60°
B=30°
The first figure matches the description