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Firdavs [7]
2 years ago
15

A 4.45 g object moving to the right at 18.6 cm/s makes an elastic head-on collision with an 8.9 g object that is initially at re

st.
18.6 cm/s
4.45 g
8.9 g
Find the velocity of the first object immediately after the collision. The acceleration of gravity is 9.8 m/s 2 . Answer in units of cm/s.
Physics
1 answer:
scoundrel [369]2 years ago
4 0

Answer:

v₁f = -6.2 cm/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

        m_{1} *v_{1o} = m_{1}* v_{1f} + m_{2}* v_{2f}

  • As the collision is elastic, total kinetic energy must be conserved also:

       \frac{1}{2}*m_{1}*v_{1o}^{2} = \frac{1}{2}*m_{1}*v_{1f} ^{2} + \frac{1}2}*m_{2}*v_{2f}^{2}

  • From the givens, we know that m₂ = 2* m₁
  • Replacing in the above equations, rearranging both sides and simplifying, we can find the following expression for v₁f:

       v_{1f} = \frac{-m_{1} }{3*m_{1}} *v_{1o} =\frac{-v_{1o}}{3} = -\frac{18.6 cm/s}{3} = -6.2 cm/s

  • v₁f = -6.2 cm/s (which means that it bounces back after the collision).
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Explanation:

So if we draw the vectors of a 2d graph we see that the difference in angles is  = 83 - 44.3 = 83-44.3=38.7^{\circ}

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Using the law of cosine, d^2 representing the distance between the planes, we see that:

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You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 252 N in the negative x di
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- the frictional force, Ff, pulling backward

In this case, the refrigerator is not moving: this means that its acceleration is zero. According to Newton's second law, this also means that the net force acting on the refrigerator is also zero:

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