A 4.45 g object moving to the right at 18.6 cm/s makes an elastic head-on collision with an 8.9 g object that is initially at re
1 answer:
Answer:
v₁f = -6.2 cm/s
Explanation:
- Assuming no external forces acting during the collision, total momentum must be conserved, as follows:
- As the collision is elastic, total kinetic energy must be conserved also:
- From the givens, we know that m₂ = 2* m₁
- Replacing in the above equations, rearranging both sides and simplifying, we can find the following expression for v₁f:
- v₁f = -6.2 cm/s (which means that it bounces back after the collision).
You might be interested in
Here in this case we can use work energy theorem
As per work energy theorem
Work done by all forces = Change in kinetic Energy of the object
Total kinetic energy of the solid sphere is ZERO initially as it is given at rest.
Final total kinetic energy is sum of rotational kinetic energy and translational kinetic energy
also we know that
Now kinetic energy is given by
Now by work energy theorem
Work done = 10500 - 0 = 10500 J
So in the above case work done on sphere is 10500 J