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avanturin [10]
3 years ago
8

A sample of helium gas is heated from 20.0°C to 40.0°C. This

Chemistry
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

C. 548mL

Explanation:

Attached is an image of the explanation. Hope this helps!

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For the following reaction,
jeka94

Answer:

The answer to your question is:

1.- CO

2.- 0.414 moles of CO2

Explanation:

Data

                               2CO   + O2      ⇒    2CO2

CO = 0.414 moles

O2 = 0.418

 

Process

theoretical ratio   CO/O2 = 2/1 = 1

experimental ratio  CO/O2 = 0.414/0.418 = 0.99

Then the limiting reactant is CO

2.-

                    2 moles of CO ---------------  2 moles of CO2

                    0.414 moles of CO ---------  x

                   x = (0.414 x 2) / 2

                   x = 0.414 moles of CO2

                   

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