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Svetllana [295]
3 years ago
6

HELP Find the least common denominator (LCD) of eight ninths and 1 and one third.

Mathematics
2 answers:
ElenaW [278]3 years ago
4 0

Answer:

9

Step-by-step explanation:

Ludmilka [50]3 years ago
3 0

9 is the LCD of 8/9 and 1/3. please mark thanks!

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Ill mark brainliest !!
Solnce55 [7]

Answer:

The answer is true.

3 0
2 years ago
Read 2 more answers
Scientists want to know the total trout population in a part of Lake Michigan. They tagged and released 200 trouts back into the
blondinia [14]
The estimate would be 1200.

We will set up a proportion for this.  10 out of 60 of the sample were tagged, so that is the first ratio.  The 200 that were tagged would be in the numerator of the second ratio (10 was the portion tagged, and 200 is the portion tagged, so they both go on top).  We do not know the total number so we use a variable:

10/60 = x/200

Cross multiply:

10*x = 60*200
10x = 12000

Divide both sides by 10:
10x/10 = 12000/10
x = 1200
6 0
3 years ago
What’s 4/5 times 2/3
maxonik [38]

Answer:

8/15

Step-by-step explanation:

When multiplying fractions, simply multiply the numbers straight across. First, multiply the numerators to get 8. Then, multiply the denominators and you'll get 15.

6 0
3 years ago
Read 2 more answers
A polygon has vertices at (-1,1), (1,1), (1,-1) & (-1,-1) what is the perimeter in units of the polygon
sukhopar [10]

Answer:

8

Step-by-step explanation:

5 0
3 years ago
Risk taking is an important part of investing. In order to make suitable investment decisions on behalf of their customers, port
GrogVix [38]

Answer:

a=49.5 -1.28*15=30.3

So the value of height that separates the bottom 10% of data from the top 90% is 30.3.  

If the score is lower than 30.3 we consider this score as risk averse

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(49.5,15)  

Where \mu=49.5 and \sigma=15

We are interested in the bottom 10% of the data.

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.9   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.1 of the area on the left and 0.9 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.1 and P(z>-1.28)=0.9

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.28

And if we solve for a we got

a=49.5 -1.28*15=30.3

So the value of height that separates the bottom 10% of data from the top 90% is 30.3.  

If the score is lower than 30.3 we consider this score as risk averse

7 0
3 years ago
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