<h3>Given</h3>
- room height is x feet
- room length is 3x feet
- room width is 3x feet
- a door 3 ft wide by 7 ft tall
<h3>Find</h3>
- The net area of the wall, excluding the door
<h3>Solution</h3>
The area of the wall, including the door, is the room perimeter multiplied by the height of the room. The room perimeter is the sum of the lengths of the four walls.
... gross wall area = (3x +3x +3x +3x)·x = 12x²
The area of the door is the product of its height and width.
... door area = (7 t)×(3 ft) = 21 ft²
Then the net wall area, exclusive of the door is ...
... net wall area = gross wall area - door area
... net wall area = 12x² -21 . . . . square feet
1.When all the three cut outs of the angles A, B, C placed adjacent to each other at a point, then it forms a line forming a straight angle, i.e. 180°.
Flence, it is proved that the sum of the three angles of a triangle is 180°.
Therefore, ∠A + ∠B + ∠C =180
Answer:
The value of SecФ is 
.
Step-by-step explanation:
Given as for trigonometric function :
tan²Ф = 
Or, tanФ = 
∵ tanФ = 
So, =
So, Hypotenuse² = perpendicular² + base²
or, Hypotenuse² = ( 
)² + ( 
)²
Or, Hypotenuse² = 3 + 8 = 11
Or, Hypotenuse = ( 
)
Now SecФ = 
or, SecФ = 
= 
<u>Second Method</u>
Sec²Ф - tan²Ф = 1
Or, Sec²Ф = 1 + tan²Ф
or, Sec²Ф = 1 +
Or, Sec²Ф = 
Or, SecФ =
Hence The value of SecФ is . Answer
Start by completely ignoring the paralelagram.
Let's choose the top triangle as our starter.
To get the top triangle to the position of the bottom triangle, you must translate it.
First, find how many units the first triangle must move down to reach the same level as the bottom triangle, (i'll let you figure it out bu numbering this as a question) 1.<u> </u>
Next, your first triangle should need to move left to reach the position of the second triangle. How many units left does the first triangle need to move?
2.<u> </u>
<u>You moved the first triangle *Blank* units down and *Blank* units left.</u>
Lastly, you need to look at your paralelagram.
Take the same movements you did with the two triangles and transfer them to the nessacary point of the paralelagram.
<em><u>If you need and extra help, or need more explanation, ask in the comments section. I also recomend that you tell me what you got as your answers to one and two so that you can make sure you got the answer correct.</u></em>
Answer:
im not the best at algebra but
2a+3b+4c
Step-by-step explanation:
subtract
(2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).
add
=(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)
=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)
=4a+8c
then subtract
=(4a+8c)−(2a−3b+4c)
=4a+8c−2a+3b−4c
=2a+3b+4c
