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3 years ago

State the principle of quantization of charge

Physics

2 answers:

Svetach [21]3 years ago

8 0

Answer:

Charge quantization is the principle that the charge of any object is an integer multiple of the elementary charge

maw [93]3 years ago

3 0

Answer: Charge quantization is the principle that the charge of any object is an integer multiple of the elementary charge. Thus, an object's charge can be exactly 0 e, or exactly 1 e, −1 e, 2 e, etc., but not, say, 12 e, or −3.8 e

Explanation:

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Will the temperature of a plastic or wooden spoon be more than the temperature of a metal spoon if you put both of these in a cu

Alja [10]

Answer:

Explanation:

the metal spoon would be higher temperature

7 0

3 years ago

Read 2 more answers

The Achilles tendon is a fibrous tissue that connects your soleus to your calcaneus and can withstand 145 MPa of tensile stress.

Mnenie [13.5K]

Answer:

F = 1.2 10⁵ N

Explanation:

Force is defined by

P = F / A

F = P A

The area is

A = π r²

the radius is half the diameter

r = d / 2

A = π d²/4

we substitute

F = P π d²/4

let's calculate

F = 145 10⁶ π (3.25 10⁻²)²/4

F = 1.2 10⁵ N

5 0

3 years ago

Question 10 of 34

labwork [276]

Julia walks from the park, which is six blocks east of her house, to the store, which is three blocks east of her house. Julia walks for 5 minutes. This walk's average speed will be 1.2 blocks per minute. Option B is correct.

<h3>What is displacement?</h3>

Displacement is defined as the shortest distance between the two points. Distance is the horizontal length covered by the body. While displacement is the shortest distance between the two points.

Displacement is a vector quantity .its unit is m.

The average velocity on this walk will be;

$\rm v_{avg}= \frac{d}{t} \\\\ \rm v_{avg}= \frac{6 \ block+ 3 \ block }{5 \ minute } \\\\ v_{avg}=1.4 \ block /min$

Hence option B is correct.

To learn more about displacement refer to the link; brainly.com/question/10919017

#SPJ1

3 0

2 years ago

Public television station KQED in San Francisco broadcasts a sinusoidal radio signal at a power of 777 kW. Assume that the wave

ehidna [41]

Answer:

A) P = 3.3 × 10^(-11) Pa

B) Amplitude of electric field = 1.931 N/C

Amplitude of magnetic field = 6.44 × 10^(-9) T

C) μ_av = 1.65 × 10^(-11) J/m³

D) 50% each for the electric and magnetic field

Explanation:

A) First of all let's calculate intensity.

I = P_av/A

We are given;

P_av = 777 KW = 777,000 W

Distance = 5 km = 5000 m

Thus;

I = 777000/(2π × 5000²)

I = 0.00495 W/m²

Now, the average pressure would be given by the formula;

P = 2I/C

Where C is speed of light = 3 × 10^(8) m/s

P = (2 × 0.00495)/(3 × 10^(8))

P = 3.3 × 10^(-11) Pa

B) Formula for the amplitude of the electric field is gotten from;

E_max = √[2I/(εo•c)].

Where εo is the Permittivity of free space with a constant value of 8.85 × 10^(−12) c²/N.mm²

I and c remain as before.

Thus;

E_max = √[(2 × 0.00495)/(8.85 × 10^(−12) × 3 × 10^(8))]

E_max = √3.72881355932

E_max = 1.931 N/C

Formula for amplitude of magnetic field is gotten from;

B_max = E_max/c

B_max = 1.931/(3 × 10^(8))

B_max = 6.44 × 10^(-9) T

C) Formula for average density is;

μ_av = εo(E_rms)²

Now, E_rms = E_max/√2

Thus;

E_rms = 1.931/√2

μ_av = 8.85 × 10^(−12) × (1.931/√2)²

μ_av = 1.65 × 10^(-11) J/m³

D) The energy density for the electric and magnetic field is the same. So both of them will have 50% of the energy density.

4 0

3 years ago

a block accelerates at 3.3 m/s^2 down a plane inclined at an angle of 27°. find the kinetic friction coefficient between the blo

finlep [7]

Answer:

0.13

Explanation:

Draw a free body diagram. There are three forces:

Weight force mg pulling down.

Normal force N pushing perpendicular to the incline.

Friction force Nμ pushing parallel up the incline.

Sum of the forces perpendicular to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces parallel down the incline:

∑F = ma

mg sin θ − Nμ = ma

mg sin θ − mgμ cos θ = ma

g sin θ − gμ cos θ = a

gμ cos θ = g sin θ − a

μ = (g sin θ − a) / (g cos θ)

Given a = 3.3 m/s² and θ = 27°:

μ = (9.8 m/s² sin 27° − 3.3 m/s²) / (9.8 m/s² cos 27°)

μ = 0.13

3 0

3 years ago

State the principle of quantization of charge​

State the principle of quantization of charge