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3 years ago

How many neutrons does element X have if its atomic number is 23 and its mass number is 87?

2 answers:

6 0

The periodic table, surprisingly, carries much more info than most would think. Each item is in a specific place that accurately puts it into several precise categories at once, which scientists utilize constantly.

In this case, one of those categories is the atomic number and mass number. These together hod the key to finding out the composition of the nucleus.
The atomic number in elements is how many protons are in the nucleus. As you should know, a nucleus contains BOTH protons and neutrons. This is what is represented by the MASS number, which is protons +neutrons. (ignoring anything after the decimal point)

So, if Element has an atomic number (protons) of 23, and a mass number of 87, this means 23+neutrons=87. Do the inverse. 87-23=64
This means element X has 23 protons, 64 neutrons, and 23 electrons (assuming it's electrically neutral).

The answer of neutrons is 64
Hope this helps!

snow_lady [41]3 years ago

5 0

Answer:
100

The atomic mass of an element can be thought of as the number of protons + the number of neutrons. The atomic number of an element equals the amount of protons it has. Using this, we see that the number of neutrons can be calculated by subtracting the atomic number from the atomic mass. In this case, we get
153
−
53
=
100
.

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What is Markanikov rule?

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134 grams of nitric acid is added to 512 grams of water. Calculate the molality of nitric acid.

Nana76 [90]

Answer: 4.15234 m

512 g H2O * $\frac{1 kg}{1000 g}$ = 0.512 kg H2O

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H = 1.008 g/mol

N = 14.007 g/mol

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3 years ago

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A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

Answer: The mass of glucose in final solution is 0.420 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

4 years ago

In the reaction between copper sulphate solution and sodium sulphide solution, 15.9 g copper sulphate completely reacts with 7.8

nikitadnepr [17]

Answer:

The mass of formed sodium sulphate solution is 14.2 g.

Explanation:

From the given,

Mass of copper sulphate = 15.9 g

Mass of sodium sulphide = 7.8 g

Total mass of reactant = Mass of copper sulphate + Mass of sodium sulphide

= 15.9 + 7.8g = 23.7g

Mass of copper sulphide formed = 9.5 g

Mass of sodium sulphate = Total mass - Mass of copper sulphide

= 23.7 g - 9.5 g = 14.2 g

Therefore, The mass of formed sodium sulphate solution is 14.2 g.

8 0

3 years ago

How many monochlorination products can be formed (constitutional isomers only) from the reaction of (CH3)2CHCH2CH3 with Cl2 and

faltersainse [42]

Answer:

4 monochlorination products can be formed.

Explanation:

Constitutional isomers : These are those compounds with same molecular formula but different atomic arrangement.For example: butane and 2-methly-propane.

On monochlorination of 2 methyl-butane we will have four possibilities of product which will be constitutional isomers of each other:

1-chloro-3-methyl butane : $(CH_3)_2CH-CH_2-CH_2-Cl$

2-chloro-3-methyl butane : $(CH_3)_2CH-CHCl-CH_3$

2-chloro-2-methyl butane $(CH_3)_2CCl-CH_2-CH_3$
1-chloro-2-methyl butane $(CH_2Cl)_2CH-CH_2-CH_3$

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3 years ago