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aev [14]
3 years ago
6

Which situation would most likely show a positive association?

Mathematics
1 answer:
Kitty [74]3 years ago
3 0

Answer:

B. the weight of a dog and the amount of food it eats per day.

This is because dogs only eat around 1/3 of their body weight a day, hence the dogs weight having a positive comparison value to the weight of the food that it eats.

Hope this helps!

Answer: B

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A certain manufactured item is visually inspected by two different inspectors. When a defective item comes through the line, the
andreev551 [17]

The fraction of a defective item getting by both inspectors is \frac{5}{100} = \frac{1}{20}

Step-by-step explanation:

Step 1; Assume that the probability of the first inspector missing a defective part is P(A) and the probability of the second inspector missing those that do get past the first inspector is P(B).

Step 2; It is given that P(A) = 0.1, we convert this into a fraction so that the final probability will be a fraction and not a decimal.

P(A) = 0.1 = \frac{1}{10}.

It is given that the second inspector misses 5 out of 10 that get past the first inspector, so P(B) = \frac{5}{10}.

Step 3; To calculate the probability of both inspectors missing a defective part, we multiply both the probabilities.

P(A and B happening) = P(A) × P(B) = \frac{1}{10} × \frac{5}{10} = \frac{5}{100} = \frac{1}{20} = 0.05%. So there is a 0.05% chance of both inspectors missing a defective part.

8 0
3 years ago
ANIMALS A chicken can run at a top speed of 9 miles per hour. Find the top speed of a chicken in miles per minute. Round to the
NISA [10]
<span>
1.You first have to determine the relationship and the current unit and the target unit which it will be converted into....</span> <span>
2.In this case, feet to meters and seconds to minutes</span> <span>
3.Determine the conversion rate</span>
<span>4 <span>The time which is 2 mi / hr x 1 hr / 60 min =  0.3 mi/min</span></span><span> 
</span><span>And that's your answer :)</span>
5 0
4 years ago
Help Help Me Plzzzzzzzzzzzzzzzzzzzzz <br>I don't understand this problems
natita [175]

Answer:

  1. lower right (see attachment 1)
  2. 39
  3. linear/exponential (see attachment 2)

Step-by-step explanation:

<h3>1.</h3>

An exponential function is one that increases or decreases at a rate that is proportional to its value. That is, if it is increasing, it does so at an increasing rate. If it is decreasing, it does so at a decreasing rate.

The "base" of the function is the number in parentheses when the function is written as it is here. The multiplier is the number to the left of these parentheses, and the exponent is the small number or expression to the upper right of the parentheses.

If the "base" is less than 1, then the function will be decreasing. If there is no added constant, it will decrease toward zero. If there is an added constant (as here, -1), then the function will decrease toward that value. The only graph showing a function decreasing toward -1 is the one at lower right (attachment 1).

___

<em>Note about the multiplier</em>

If the multiplier is negative (not the case here), then the graph will be reflected across the x-axis and the descriptors "increasing" and "decreasing" get reversed. A graph that would go down to the right with a positive multiplier goes up to the right with a negative multiplier.

What you can <em>always</em> say is that when the base is less than 1, the graph is steep on the left and flat on the right. For a base greater than 1, the reverse is true.

<h3>2.</h3>

The average rate of change of a function between x1 and x2 is given by the formula ...

... average rate of change = (f(x2) -f(x1))/(x2 -x1)

Here, you have x2 = 10, so f(x2) = 3^(10/2) = 3^5 = 243; and x1 = 4, so f(x1) = 3^(4/2) = 3^2 = 9.

Then the average rate of change is ...

... average rate of change = (243 -9)/(10 -4) = 234/6 = 39 . . . flowers/day

<h3>3.</h3>

When faced with determining the sort of function you have, first of all check the given x-values. If they are evenly spaced, as here, then you are in luck.

Next look at the differences of y-values. These are the "first differences". For the first table, they are ...

  • 7 - 5.5 = 1.5
  • 8.5 - 7 = 1.5 . . . . same as the other one

When the first differences are constant, as here, the function is linear.

In the second table, the first differences are decidedly <u>not</u> constant, so the function is not linear. Another test you can do is to see if the ratios of y-values are a constant. Here, those ratios are ...

  • 8/1 = 8
  • 64/8 = 8

These ratios are constant, so the function is exponential.

6 0
3 years ago
Is there any option to to 1 not be equal to 1?
r-ruslan [8.4K]

No.  1 is is always equal to to 1 .

4 0
3 years ago
Why is 3/4 greater thab 11/16 how can i be sure
Delicious77 [7]
You can make them have the same denominator and then compare

( \frac{3}{4}) ( \frac{16}{16}) =  \frac{48}{64}

(\frac{11}{16})( \frac{4}{4}) =  \frac{44}{64}

so as you can see, \frac{3}{4} is \frac{4}{64} bigger than  \frac{11}{16}
5 0
3 years ago
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