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ipn [44]
3 years ago
8

Round .1325 to the thousandths place

Mathematics
1 answer:
lana66690 [7]3 years ago
4 0
0.1325 rounded to the nearest thousandths place is 0.133
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five dvds are packaged in plastic wrap. five packages are packed in a box. five boxes are packed in a crate. how many dvds are p
Gnesinka [82]

The question is an illustration of proportion and exponents

The number of dvd is one crate is: \mathbf{5^3\ dvds}

From the question, the given parameters are:

<em />\mathbf{5\ dvd = 1\ wrap}<em> ---- 5 dvds in 1 package</em>

<em />\mathbf{5\ package = 1\ box}<em> --- 5 packages in 1 box</em>

<em />\mathbf{5\ boxes = 1\ crate}<em> --- 5 boxes in 1 crate</em>

<em />

The number of dvds in 1 crate is calculated as follows:

\mathbf{5\ boxes = 1\ crate}

Substitute 5 packages for 1 box in the above equation

\mathbf{5 \times 5\ packages = 1\ crate}

Substitute 5 dvds for 1 package in the above equation

\mathbf{5 \times 5 \times 5\ dvd= 1\ crate}

Apply law of indices

\mathbf{5^{1 + 1 + 1}\ dvd= 1\ crate}

Express properly as:

\mathbf{5^3\ dvd= 1\ crate}

Rewrite as:

\mathbf{1\ crate = 5^3\ dvd}

Hence, the number of dvd is one crate is: \mathbf{5^3\ dvds}

Read more about proportion and exponents

brainly.com/question/12787584

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3 years ago
Find the area of the figure.
lys-0071 [83]

Answer: 13300

Step-by-step explanation:

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3 years ago
Plz help..................refresh page before u answer
S_A_V [24]
\dfrac{7}{x^2-36}-\dfrac{1}{x-6}=\dfrac{7}{(x+6)(x-6)}-\dfrac{1}{x-6}=\\\\\\=&#10;\dfrac{7}{(x+6)(x-6)}-\dfrac{(x+6)}{(x+6)(x-6)}=\dfrac{7-x-6}{(x+6)(x-6)}=\boxed{\dfrac{1-x}{(x+6)(x-6)}}

Answer B.
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Can any one help me??????
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First One! All you have to do is count the example and see if there is a match!
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HELP ASAP PLS, matching sequence to its recursive formula
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A to goes to iv; B goes to ii; C goes to i; D goes to iii
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