Note down the formula below
![\boxed{\sf Mass\%\;of\; element=\dfrac{Mass\:of\:the\: element}{Mass\;of\:the\: compound}\times 100}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20Mass%5C%25%5C%3Bof%5C%3B%20element%3D%5Cdfrac%7BMass%5C%3Aof%5C%3Athe%5C%3A%20element%7D%7BMass%5C%3Bof%5C%3Athe%5C%3A%20compound%7D%5Ctimes%20100%7D)
Mass of the compound
![\\ \sf\longmapsto 15+120=135g](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%2015%2B120%3D135g)
Mass % of Hydrogen:-
![\\ \sf\longmapsto \dfrac{15}{135}\times 100](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B15%7D%7B135%7D%5Ctimes%20100)
![\\ \sf\longmapsto \dfrac{1}{9}\times 100](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B1%7D%7B9%7D%5Ctimes%20100)
![\\ \sf\longmapsto 11.1\%](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%2011.1%5C%25)
Mass % of Oxygen:-
![\\ \sf\longmapsto \dfrac{120}{135}\times 100](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B120%7D%7B135%7D%5Ctimes%20100)
![\\ \sf\longmapsto \dfrac{8}{9}\times 100](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B8%7D%7B9%7D%5Ctimes%20100)
![\\ \sf\longmapsto 88.9\%](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%2088.9%5C%25)
First calculate the mole fraction of each substance:
Acetone: 2.88 mol ÷ (2.88 mol + 1.45 mol) = 0.665
Cyclohexane: 1.45 ÷ (2.88 mol + 1.45 mol) = 0.335
Raoult's Law: P(total) = P(acetone) · χ(acetone) + P(cyclohexane) · χ(cyclohexane).
P(total) = 229.5 torr · 0.665 + 97.6 torr · 0.335
P(total) = 185.3 torr
χ for acetone: 229.5 torr · 0.665 ÷ 185.3 torr = 0.823
χ for cyclohexane: 97.6 torr · 0.335 ÷ 185.3 torr = 0.177
Answer:
Player B
Explanation:
I just did it and I got it right :)
The one that is observed or measured in the experiment, and it is known as the dependent variable.