Answer:
49.2 g/mol
Explanation:
Let's first take account of what we have and convert them into the correct units.
Volume= 236 mL x (
) = .236 L
Pressure= 740 mm Hg x (
)= 0.97 atm
Temperature= 22C + 273= 295 K
mass= 0.443 g
Molar mass is in grams per mole, or MM= 
or MM= 
. They're all the same.
We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be
n=
, where R (constant)= 0.082 L atm mol-1 K-1
Let's plug in what we know.
n=
n= 0.009 mol
Let's look back at MM= and plug in what we know.
MM= 
MM= 49.2 g/mol
Answer: The percent ionization of a monoprotic weak acid solution that is 0.188 M is 
Explanation:
Dissociation of weak acid is represented as:
cM 0 0
So dissociation constant will be:
Give c= 0.188 M and 
= ?
Putting in the values we get:
Thus percent ionization of a monoprotic weak acid solution that is 0.188 M is
Answer:
P₂ = 1530.1 KPa
Explanation:
According to Bolye's Law,
The volume of given mass of a gas is inversely proportional to the pressure applied on it at a constant temperature.
V∝1/P
V = kP
V = K/P
PV = k
According to this equation,
P₁V₁ = P₂V₂
Given data:
Initial volume = 456 dm³
Initial pressure = 101 KPa
Final volume = 30.1 dm³
Final pressure = ?
Solution:
Formula:
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 101 KPa × 456 dm³ / 30.1 dm³
P₂ = 46056 / 30.1 dm³
P₂ = 1530.1 KPa
