1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tigry1 [53]
3 years ago
14

HURRY FAST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
2 answers:
miss Akunina [59]3 years ago
8 0
B. The sand increases friction by increasing roughness.
Nat2105 [25]3 years ago
5 0

Answer:

B. The sand increases friction by increasing roughness.

  • Explanation: bc

You might be interested in
Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin
DanielleElmas [232]

Answer:

74.4 ml

Explanation:

          C₆H₈O₇(aq) + 3NaHCO₃(s) => Na₃C₆H₅O₃(aq + 3CO₂(g) + 3H₂O(l)

Given     15g = 15g/84g/mol = 0.1786mole Sodium Bicarbonate

From equation stoichiometry 3moles NaHCO₃ is needed for each mole citric acid or, moles of citric acid needed is 1/3 of moles sodium bicarbonate used.

Therefore, for complete reaction of 0.1786 mole NaHCO₃ one would need 1/3 of 0.1786 mole citric acid or 0.0595 mole H-citrate.

The question is now what volume of 0.8M H-citrate solution would contain 0.0595mole of the H-citrate? This can be determined from the equation defining molarity. That is => Molarity = moles solute / Liters of solution

=> Volume (Liters) = moles citric acid / Molarity of citric acid solution

=> Volume needed in liters = 0.0.0595 mole/0.80M = 0.0744 Liters or 74.4 ml

6 0
3 years ago
What happens to a river that’s is blocked from a landslide?
DanielleElmas [232]

Answer:

A

Explanation:

6 0
2 years ago
What mass of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
iren [92.7K]

91.4 grams

91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

C = mol/volume

2.45M=mol/0.5L

2.45M⋅0.5L = mol

mol = 1.225

Convert no. of moles to grams using the atomic mass of K + Cl

1.225mol * \frac{39.1+35.5}{mol}

mol=1.225

=1.225 mol . \frac{74.6g}{mol}

=1.225 . 74.6

=91.4g

therefore, 91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

What is 1 molar solution?

In order to create a 1 molar (M) solution, 1.0 Gram Molecular Weight of the chemical must be dissolved in 1 liter of water.

58.44 g make up a 1M solution of NaCl.

To learn more about molar solution visit:

brainly.com/question/10053901

#SPJ4

3 0
1 year ago
What is the mass, in grams, of potassium in 12.5 g of k
anyanavicka [17]

Answer:

Option d)3.32 g is correct.

Explanation:

hope this helps

7 0
3 years ago
What elements is mercuric oxide composed of?
Tomtit [17]

Answer:

Lavoisier reacted mercury with oxygen to form mercuric oxide

5 0
2 years ago
Read 2 more answers
Other questions:
  • What is the molarity of a 5.00x10^2 mL solution containing 21.1 g of potassium bromide (KBr)? The molar mass of KBr is 119.0 g/m
    6·2 answers
  • A student determines that she used 0.0665 mol of sodium hydroxide (NaOH) to completely titrate 25.00 mL of sulfuric acid solutio
    13·2 answers
  • Water condenses onto grass in the early morning when the air is clear because...
    13·2 answers
  • Why are there two high tides a day about 12 hours apart?<br>​
    9·1 answer
  • [Help, Help, Help! Stoichiometry and Gases, please explain]
    13·2 answers
  • Density is the ratio of mass to volume. Another way to say this is
    7·1 answer
  • _____ stars can be between one thousand times dimmer and one million times brighter than the Sun.
    11·1 answer
  • What is the pH of a solution that has a [OH-] 2.65*10 -9 M
    11·1 answer
  • Use the periodic table to answer the questions which is the correct electron configuration for titanium
    6·1 answer
  • Methane burns in the presence of oxygen to form carbon dioxide and water.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!